Question

这是我的代码：

    import java.util.*;
public class Game {
    public static void main(String[] args) {
        Random rand = new Random();
        Scanner scan = new Scanner(System.in);
        boolean guessed = false;
        int randInt = rand.nextInt(10000) + 1;

        System.out.println("Guess my number. It's between 1 and 10,000.");

        while (!guessed) {
            int guess = 0;
            do {
                if(!scan.hasNextInt()) {
                    String notInt = scan.next();
                    System.out.printf("%s is not an integer.\n", notInt);
                }
                else
                    guess = scan.nextInt();
            }while (guess == 0);

            if(guess > randInt) {
                System.out.println(guess + " is too high.");
            }
            else if(guess < randInt) {
                System.out.println(guess + " is too low.");
            }
            else if (guess == randInt) {
                System.out.println(guess + " is the number!");
                guessed = true;
            }

        }
    }

}

这是数字猜测游戏，计算机生成1到10,000之间的随机数，用户必须通过提示猜测它。我的问题是如何在每次猜测后让控制台输出新的猜测范围？假设用户猜测5000并且控制台说“5000太高了”。在猜测之后，我希望有一个猜测范围的打印。由于5000太高，我想控制台打印猜猜是在1到5000之间。然后让我们说用户猜测400.“400太低了。” 猜猜是在400到5000之间。在每次猜测后，我需要做些什么才能使控制台打印新的猜测范围？谢谢。

Answer 1

您可以通过执行以下操作来优化代码：

import java.util.Random;
import java.util.Scanner;

public class Game {

  public static void main(String[] args) {

     Random rand = new Random();
     Scanner scan = new Scanner(System.in);
     int randInt = rand.nextInt(10000) + 1;
     int max=10000, min=1, counter=1;

     while(true){
         try{
             System.out.printf("Guess my number. It's between %d and %d:\n",  min, max);
             int guess = Integer.parseInt(scan.nextLine());

             if((guess>randInt && guess<=10000)){
                 System.out.println(guess + " is too high!"); 
                 max=guess;
             }
             else if(guess<randInt && guess>=1){
                 System.out.println(guess + " is too low!"); 
                 min=guess;
             }
             else if(guess==randInt){
                 System.out.println(guess + " is the number! After " + counter + " attempt");
                 break;
            } 
            counter++;   
         }
         catch(NumberFormatException e){
             System.out.println("Please Insert Only Integers!");
             continue;
         }
     }
     scan.close();
  }
}

<强>测试

如何运作？

读取每个循环中的整行，并解析它，如果输入无效，则会抛出异常，因此您会通知用户。
如果它是有效输入，请通过将其与随机数进行比较来评估它。
根据猜测数字，您可以更改max或min值。
这种方式可以防止用户超越上层和上层。下限（，即1和10000 ）。
如果猜测正确，请打破循环。因此，您不需要使用额外的boolean变量。

Answer 2

你可以有两个整数，upperRange和lowerRange。每当用户猜测太高时，将upperRange设置为用户的猜测。同样适用于lowerRange。

int upperRange;
int lowerRange;
if(guess > randInt) {
            System.out.println(guess + " is too high.");
            upperRange = guess;

} else if(guess < randInt) {
            System.out.println(guess + " is too low.");
            lowerRange = guess;
}
System.out.println("Guessing range: " + lowerRange + "-" + upperRange);

数字猜测游戏。如何打印猜测范围？

2 个答案: