与ARM的持久TCP连接

Question

我正在尝试编写一个简单的TCP服务器，但我遇到的问题是套接字在第一次运行后被关闭（顺便说一下，它在一个线程中运行）。我可以尝试在没有ARM（自动资源管理）的情况下重写它，在try之后用圆形方块进行重写 - 但我宁愿保留它。

那么，有没有办法在Java中使用ARM编写一个简单的持久性TCP服务器？

public class Server {
/* Server */

public int port = 8088;

public Server (int port){
    this.port = port;
    System.out.println("Will listen on port " + this.port);
}

public Server () {
    System.out.println("Will listen on default port " + port);
}

public void start() {

    try (ServerSocket initSocket = new ServerSocket(port);
         Socket socket = initSocket.accept();
         BufferedReader bfin = 
                 new BufferedReader(new InputStreamReader(socket.getInputStream()));
         BufferedOutputStream bfout =
                 new BufferedOutputStream(socket.getOutputStream())  
         )
    {
        String line = bfin.readLine();
        while (line != null && !"BYE\n".equals(line)){
            String answer = parseadd(line) + "\n";
            System.out.println("From client: " + line);
            bfout.write(answer.getBytes());
            bfout.write("BYE\n".getBytes());
            bfout.flush();
            line = bfin.readLine(); 
        }
        System.out.println("Exiting server while loop!");
    } 
    catch (IOException e) {
        System.out.println("Exception caught when trying to");
        System.out.println(e.getMessage());
    }

}


}