urllib2 httplib.BadStatusLine

时间:2017-06-27 15:34:42

标签: python http

我正在使用python urllib2连接HTTP服务器。有时我得到回复:httplib.BadStatusLine: ''

我的代码:

response = None
try:
    request = urllib2.Request(http_url,params)
    response = urllib2.urlopen(request,timeout=5000)
    return str(response.read())
except urllib2.HTTPError :
    return ""
except urllib2.URLError:
        return ""

响应错误:

  File "/usr/lib64/python2.7/urllib2.py", line 154, in urlopen
    return opener.open(url, data, timeout)
  File "/usr/lib64/python2.7/urllib2.py", line 431, in open
    response = self._open(req, data)
  File "/usr/lib64/python2.7/urllib2.py", line 449, in _open
    '_open', req)
  File "/usr/lib64/python2.7/urllib2.py", line 409, in _call_chain
    result = func(*args)
  File "/usr/lib64/python2.7/urllib2.py", line 1244, in http_open
    return self.do_open(httplib.HTTPConnection, req)
  File "/usr/lib64/python2.7/urllib2.py", line 1217, in do_open
    r = h.getresponse(buffering=True)
  File "/usr/lib64/python2.7/httplib.py", line 1051, in getresponse
    response.begin()
  File "/usr/lib64/python2.7/httplib.py", line 415, in begin
    version, status, reason = self._read_status()
  File "/usr/lib64/python2.7/httplib.py", line 379, in _read_status
    raise BadStatusLine(line)
httplib.BadStatusLine: ''

我不知道如何解决这个错误?我不知道为什么会收到错误回复。

0 个答案:

没有答案