Question

基本上我有一个非常简单地加密消息的功能。

def encrypt(message):
    alphabet = ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"]
    key = ["4","x","z","@","%","b","j","q","(","ƒ","¥","µ","˚","nå","ø","π","å","œ","¢","∞","∫","µ","≈","`","¬","…"]
    new_message = ""
    for x in range(0,len(message)):
        new_message = message.replace(message[x],key.index[alphabet.index(message[x])])
    return new_message

print(encrypt(input("What would you like to encrypt").lower()))

这应该取信并将其替换为list键中具有相同索引的字符，但是我收到错误：

TypeError: 'builtin_function_or_method' object is not subscriptable

Answer 1

key.index()获取一个值并返回其索引，并使用()而不是[]，因此您需要修复此行：

new_message = message.replace(message[x],key.index[alphabet.index(message[x])])

为：

new_message = message.replace(message[x],key[alphabet.index(message[x])])

这将使用字母索引并使用它来访问key列表并获取该索引处的值以将其替换为原始字母。

修改更好的方法是使用dictionary并构造一个新的字符串，以避免在replace()

上加倍string
dic = {'a': '4', 'b': 'x', 'c': 'z' ...} new_message = '' for x in message: new_message += dic[x] return new_message

Answer 2

我建议使用中间console.log来创建DATA 2列表项与function testIterate() { return q.all(_.map(params.attachments, function (a) { var deferred = q.defer(); var filePath = path.join(tempDir, a.fileName); //console.log('ATTACHMENT BUFFER ::: ', a.buffer); fs.writeFile(filePath, a.buffer, function (err) { if (err) { // error } // Iterate letters to create unique keys for each attachment var letter = String.fromCharCode('A'.charCodeAt() + idx); var fileKey = "attachment" + letter; deferred.resolve( formData[fileKey] = { value: fs.createReadStream(filePath), options: { filename: a.fileName, //path: filePath, contentType: a.contentType } } ); console.log('THIS IS THE FORM DATA 1 :: ', formData); // Increment to assign unique letter to next attachment key idx++; }); return deferred.promise; })).then(function (results) { console.log('THIS IS THE FORM DATA 2 :: ', results); }); }列表项的映射：

dict

然后使用上面的字典和alphabet来转换你的字符串。例如：

key

Answer 3

最后是str.translate的用例！

def encrypt(message):
    alphabet = 'abcdefghijklmnopqrstuvwxyz'
    key = '4xz@%bjq(ƒ¥µ˚nåøπåœ¢∞∫µ≈`¬'
    table = str.maketrans(alphabet, key)

    return message.translate(table)

print(encrypt('asdsaewqeq')) # 4œ@œ4%µπ%π

请注意，key中的某个条目由两个字符组成。如果这是故意的，并且您想要用2替换单个字符，则可以手动创建转换表。

table = dict(zip(map(ord, alphabet), key))

无法找到基于密钥翻译字符串的简便方法

3 个答案: