Question

我有一张桌子：'项目'

CREATE TABLE [dbo].[Project](
    [Task_ID] [int] NULL,
    [Start_Date] [date] NULL,
    [End_Date] [date] NULL
) ON [PRIMARY]
GO

此表中的数据是 -

1   2015-10-01  2015-10-02
2   2015-10-02  2015-10-03
3   2015-10-03  2015-10-04
4   2015-10-13  2015-10-14
5   2015-10-14  2015-10-15
6   2015-10-28  2015-10-29
7   2015-10-30  2015-10-31

Start_Date和End_Date之间的差异保证1天。我需要找到这些数据序列之间缺失的空白。

期望的输出：

2015-10-05  2015-10-12
2015-10-16  2015-10-27
2015-10-29  2015-10-30

到目前为止我能够得到这么多 -

SELECT [Start_Date]
    ,MIN([End_Date]) As [End_Date]
    ,DATEDIFF(DAY, [Start_Date], MIN([End_Date])) As Duration
FROM (
    SELECT [Start_Date]
    FROM Project
    WHERE [Start_Date] NOT IN (
            SELECT [End_Date]
            FROM Project
            )
    ) A
    ,(
        SELECT [End_Date]
        FROM Project
        WHERE [End_Date] NOT IN (
                SELECT [Start_Date]
                FROM Project
                )
        ) B
WHERE [Start_Date] < [End_Date]
GROUP BY [Start_Date]

给了我这个 -

Start_Date  End_Date    Duration
2015-10-01  2015-10-04  3
2015-10-13  2015-10-15  2
2015-10-28  2015-10-29  1
2015-10-30  2015-10-31  1

有任何建议如何从这里继续进行。我真的被困在这里了。提前谢谢。

检索SQL Server中日期范围序列的间隙

0 个答案: