Question

问题：我想确定哪些记录每天没有两条记录。排名告诉我每天是否有第二条记录......

SELECT TR.tourid,
       TR.tourruntimestamp,
       TC.tourname,
       TC.tourfrequency,
       TC.unit,
       TC.division,
       RANK()
         OVER (
           PARTITION BY TR.tourid
           ORDER BY TR.tourruntimestamp) AS [Rank]
FROM   DBO.tbltourrun AS TR
       INNER JOIN DBO.tso_piml_tour_config AS TC
               ON TC.tourid = TR.tourid
WHERE  ( TC.tourfrequency = '2xDay' )
       AND ( TR.tourruntimestamp BETWEEN Dateadd(DAY, Datediff(DAY, 0, Getdate()) - 1, 0) AND Dateadd(DAY, Datediff(DAY, 0, Getdate()), 0) )

Answer 1

更一般的答案。我不知道你想用几周，几个月等做什么。

select      *

from       (SELECT        TR.TourID, TR.TourRunTimeStamp, TC.tourName, TC.tourFrequency, TC.Unit, TC.Division
                         ,count(*) OVER (PARTITION BY TR.TourID) AS cnt
            FROM            dbo.tblTourRun AS TR INNER JOIN
                                     dbo.TSO_PIML_Tour_Config AS TC ON TC.tourID = TR.TourID
            WHERE           TR.TourRunTimeStamp  BETWEEN DATEADD(day, DATEDIFF(day, 0, GETDATE()) - 1, 0) AND DATEADD(day, DATEDIFF(day, 0, GETDATE()), 0))
            ) t

where       cnt <> case TC.tourFrequency when '1xDay' then 1 when '2xDay' then 2 when '4xDay' then 4 end
;

select      *

from       (SELECT        TR.TourID, TR.TourRunTimeStamp, TC.tourName, TC.tourFrequency, TC.Unit, TC.Division, count(*) OVER (PARTITION BY TR.TourID) AS cnt
            FROM            dbo.tblTourRun AS TR INNER JOIN
                                     dbo.TSO_PIML_Tour_Config AS TC ON TC.tourID = TR.TourID
            WHERE        (TC.tourFrequency = '2xDay') AND (TR.TourRunTimeStamp  BETWEEN DATEADD(day, DATEDIFF(day, 0, GETDATE()) - 1, 0) AND DATEADD(day, DATEDIFF(day, 0, GETDATE()), 0))
            ) t

where       cnt = 1
;

Answer 2

下面是一个人为的例子，它可以让你朝着正确的方向前进。我使用一个由值组成的表来模拟您尝试使用的数据的形状（剥离与该示例无关的值）。

select a.TourId
     , b.TourDate
from (values
    (1, Convert(datetime2(0), N'2016-01-01 00:00:00'))
  , (1, Convert(datetime2(0), N'2016-01-01 04:00:00'))
  , (1, Convert(datetime2(0), N'2016-01-03 00:00:00'))
  , (1, Convert(datetime2(0), N'2016-01-04 00:00:00'))
  , (1, Convert(datetime2(0), N'2016-01-04 04:00:00'))
  , (1, Convert(datetime2(0), N'2016-01-05 00:00:00'))
  , (2, Convert(datetime2(0), N'2016-02-11 00:00:00'))
  , (2, Convert(datetime2(0), N'2016-02-11 18:00:00'))
  , (2, Convert(datetime2(0), N'2016-02-13 00:00:00'))
  , (2, Convert(datetime2(0), N'2016-02-14 00:00:00'))
  , (2, Convert(datetime2(0), N'2016-02-14 18:00:00'))
  , (2, Convert(datetime2(0), N'2016-02-15 00:00:00'))
) as a (TourId, TourRunTimeStamp)
cross apply (values(Convert(date, a.TourRunTimeStamp))) as b (TourDate)
group by a.TourId
       , b.TourDate
having Count(1) != 2; -- find ids with exactly two entries
-- having Count(1) in (2, 4); -- find ids with exactly two or four entries
-- having Count(1) % 2 = 0; -- find ids with an even number of entries

这里的逻辑很简单：将日期时间转换为日期（这是在APPLY子句中完成的，以便我们可以重用计算），在TourId + {{ 1}}，计算记录数，并过滤掉所有没有等于2的计数的结果。

Answer 3

最终SQL结果：
在一些CTE或视图的帮助下，我能够使其正常工作。

查询1-游览在日期范围（昨天）
查询2-摘要显示在Datestamp列上没有日期戳记为空的游览
查询3-错过巡视时的条件计数，因此我显示错过的路线为0

`--Get All ToursRanYesterday 
WITH toursranyesterday 
     AS (SELECT TR.tourid, 
                TR.tourruntimestamp, 
                TC.tourname, 
                TC.division, 
                TC.unit, 
                TC.tourfrequency 
         FROM   dbo.tbltourrun AS TR 
                INNER JOIN dbo.tso_piml_tour_config AS TC 
                        ON TC.tourid = TR.tourid 
         WHERE  ( TC.tourfrequency LIKE '%xDay%' ) 
                AND ( TR.tourruntimestamp 
                      BETWEEN Dateadd(day, Datediff(day, 
                                   0,Getdate()) - 1, 0) 
                                                  AND 
                      Dateadd(day, Datediff(day, 
                                   0, Getdate()), 0) )), 
     --Get Summary of xDay Tours Ran with Missing Tours 
     toursummary 
     AS (SELECT TC.tourid, 
                TC.division, 
                TC.unit, 
                TC.tourname, 
                TC.tourfrequency, 
                ( CASE 
                    WHEN EXISTS (SELECT * 
                                 FROM   toursranyesterday AS TY 
                                 WHERE  TC.tourid = TY.tourid) THEN 'NO' 
                    WHEN NOT EXISTS (SELECT * 
                                     FROM   toursranyesterday AS TY 
                                     WHERE  TC.tourid = TY.tourid) THEN 'YES' 
                  END ) AS Missed, 
                TY.tourruntimestamp 
         FROM   dbo.tso_piml_tour_config AS TC 
                FULL OUTER JOIN toursranyesterday AS TY 
                             ON TY.tourid = TC.tourid 
         WHERE  ( TC.tourfrequency LIKE '%xDay%' )) 
--Add Daily Tour Count when Missed = NO 
SELECT TS.tourid, 
       TS.division, 
       TS.unit, 
       TS.tourname, 
       TS.tourfrequency, 
       TS.missed, 
       TS.tourruntimestamp, 
       Count(CASE 
               WHEN missed = 'NO' THEN 1 
               ELSE NULL 
             END) 
         OVER ( 
           partition BY TS.tourid) AS [DailyTourCount] 
FROM   toursummary AS TS 
ORDER  BY TS.tourname `

识别日期范围中的记录间隙

3 个答案: