我在R中导入的CSV中有一个数据框,例如:
Salmon 6
Salmon 4
Salmon 7
Trout 2
Trout 3
Trout 2
我想重新安排:
Salmon 6 4 7
Trout 2 3 2
转置值分别位于新列中。
答案 0 :(得分:2)
您可以使用aggregate
:
aggregate(V2 ~ V1, data = mydata, c)
# V1 V2.1 V2.2 V2.3
# 1 Salmon 6 4 7
# 2 Trout 2 3 2
<强> 数据:的强>
read.table(text='Salmon 6
Salmon 4
Salmon 7
Trout 2
Trout 3
Trout 2', header=F, quote='"') ->
mydata
答案 1 :(得分:1)
以下是使用 public async Task<double> CalculateAverageAge()
{
var client = new MobileServiceClient(AppUrl, AppKey);
var table = client.GetTable<Person>();
var sum = 0.0;
var count = 0;
var items = await table.Take(10).ToEnumerableAsync();
while (items != null && items.Count() != 0)
{
count += items.Count();
sum += Enumerable.Sum(items, i => i.Age);
var queryResult = items as IQueryResultEnumerable<Person>;
if (queryResult != null && queryResult.NextLink != null)
{
items = await table.ReadAsync<Person>(queryResult.NextLink);
}
else
{
items = null;
}
}
return sum / count;
}
dcast
library(data.table)
dcast(setDT(mydata), V1~paste0("VN", rowid(V1)), value.var = 'V2')
# V1 VN1 VN2 VN3
#1: Salmon 6 4 7
#2: Trout 2 3 2