我遇到了gob协议的问题(或者通常是网络,我的知识很弱),我不明白为什么以下代码无法正常工作。它应该是一个维护开放TCP连接并通过它发送多个gobs的简单示例。代码将发送和接收,但通常会破坏其数据。 提前谢谢。
package main
import (
"encoding/gob"
"fmt"
"net"
"strconv"
"time"
)
type Message struct {
Msg string
}
func main() {
gob.Register(new(Message))
clientAddr, err := net.ResolveTCPAddr("tcp", "localhost:12346")
if err != nil {
fmt.Println(err)
}
serverAddr, err := net.ResolveTCPAddr("tcp", "localhost:12345")
if err != nil {
fmt.Println(err)
}
serverListener, err := net.ListenTCP("tcp", serverAddr)
if err != nil {
fmt.Println(err)
}
conn, err := net.DialTCP("tcp", clientAddr, serverAddr)
if err != nil {
fmt.Println(err)
}
serverConn, err := serverListener.AcceptTCP()
if err != nil {
fmt.Println(err)
}
done := false
go func() {
for !done {
recieveMessage(serverConn)
}
}()
for i := 1; i < 1000; i++ {
sent := Message{strconv.Itoa(i)}
sendMessage(sent, conn)
}
time.Sleep(time.Second)
done = true
}
func sendMessage(msg Message, conn *net.TCPConn) {
enc := gob.NewEncoder(conn)
err := enc.Encode(msg)
if err != nil {
fmt.Println(err)
}
}
func recieveMessage(conn *net.TCPConn) {
msg := new(Message)
dec := gob.NewDecoder(conn) // Will read from network.
err := dec.Decode(msg)
if err != nil {
fmt.Println(err)
}
fmt.Println("Client recieved:", msg.Msg)
}
答案 0 :(得分:3)
问题是解码器可以缓冲下一条消息的数据。发生这种情况时,下一个新解码器将在消息中间启动。解决方法是使用单个编码器和解码器。
func main() {
...
dec := gob.NewDecoder(conn) // Will read from network.
enc := gob.NewEncoder(serverConn)
go func() {
for !done {
recieveMessage(dec)
}
}()
for i := 1; i < 1000; i++ {
sent := Message{strconv.Itoa(i)}
sendMessage(sent, enc)
}
...
}
func sendMessage(msg Message, enc *gob.Encoder) {
err := enc.Encode(msg)
if err != nil {
fmt.Println(err)
}
}
func recieveMessage(dec *gob.Decoder) {
msg := new(Message)
err := dec.Decode(msg)
if err != nil {
fmt.Println(err)
}
fmt.Println("Client recieved:", msg.Msg)
}