Question

所以这是我的尝试，它不起作用，我不确定我需要做什么，解释这个的文档只是承认。

所以我希望这里有人知道如何做到这一点。

基本概念：我已将用户最新的个人资料图片ID存储在用户主要个人资料集合中

成员集合

{
    "_id" : ObjectId("aaaat656a464"),
    "email" : "russell@ipet.xyz",
    "personal" : {
        "name" : {
            "firstname" : "Russell",
            "lastname" : "Harrower"
        },
        "profile_id" : ObjectId("333a0e2b7acebe9b869b1b0a")
    },
    "kst" : ObjectId("111111111111g")
}

现在我想从members_media集合中获取profile_id，其中_id = profile_id

这是members_media集合

{
    "_id" : ObjectId("333a0e2b7acebe9b869b1b0a"),
    "data" : {
        "url" : "https://scontent.xx.fbcdn.net/v/t1.0-1/11659354_1625058617782022_7822649569017662262_n.jpg?oh=6e2b74b33c1c4ea4cdc0094a1ae35e14&oe=59DF809A",
        "type" : "facebook/image",
        "date" : ISODate("2017-06-21T06:16:18.580Z"),
        "profile_pic" : true
    },
    "uid" : ObjectId("111111111111g")
}

所以这是我的尝试

$check = $db->aggregate([
                        ['$unwind'=> "$members_media"],
                        ['$unwind' => ['path'=>"$members_media",  'includeArrayIndex'=>"arrayIndex"]],
                        ['$lookup'=>
                            [
                              'from'=>"members_media",
                              'localField'=>"personal.profile_id",
                              'foreignField'=>"_id",
                              'as'=>"profilepic"
                            ]
                        ]



                ]);

但是，当我运行以下内容时，它不会获得成员集合

$db = static::db()->members;
    /*$check = $db->findOne(['kst' => New MongoDB\BSON\ObjectId($_SESSION["ipet_user"]), 'personal'=>['$exists'=>true]],
                       ['personal.profile_id' => 1]
    );*/

    $check = $db->aggregate([
                    ['$lookup' =>


    [
                      'from'=>"members_media",
                      'localField'=>"members.personal.profile_id",
                      'foreignField'=>"_id",
                      'as'=>"data"
                    ]
                ],
                ['$match' => 
                   ['members.kst' => New MongoDB\BSON\ObjectId($_SESSION["user"]), 'members.personal'=>['$exists'=>true]]
                ],
                ['$unwind' => ['path' => '$members_media.data', 'includeArrayIndex' => 'arrayIndex']],
                ['$project' =>
                    ['members.profile_path'=>'$data.url']
                ]

        ]);

我的结果是

object(MongoDB\Driver\Cursor)#19 (9) { ["database"]=> string(4) "ipet" ["collection"]=> NULL ["query"]=> NULL ["command"]=> object(MongoDB\Driver\Command)#18 (1)

Answer 1

我们可以这样做

$resultData = $db->collectionName->aggregate([

                  ['$lookup' => [ 
                      'from' => 'members_media',  
                      'localField' => 'personal.profile_id',
                      'foreignField'  =>  '_id',
                      'as'  => 'profileDetail',
                   ]]]);

 $myData = array();

    foreach($resultData as $result) {
      //var_dump($result);
      array_push($myData, $result);
    }
    print_r($myData);

mongodb加入两个集合来获取数据

1 个答案: