Question

这是我在末尾插入节点的linkedlistcode。我收到错误代码转储。所以请帮我解释代码有什么问题。

如果我继续回来;在* headRef = newnode之后的最后一行;它的工作。那么为什么要返回一个无效函数呢。

struct node
{
    int data; // node format
    struct node* next;
};

void insertAtEnd(struct node** headRef, int newData)
{
    struct node* ptr;
    struct node* newnode;
    ptr = (*headRef);
    newnode = (struct node*)malloc(sizeof(struct node));
    newnode->data = newData;
    newnode->next = NULL;
    if (*headRef == NULL)
    {
        *headRef = newnode;
    }
    while (ptr->next != NULL)
    {
        ptr = ptr->next;
    }
    ptr->next = newnode;
}

Answer 1

你应该返回内部，因为在if语句之后它再次进入while循环并在末尾添加额外的节点

struct node
{
    int data; // node format
    struct node* next;
};

void insertAtEnd(struct node** headRef, int newData)
{
    struct node* ptr;
    struct node* newnode;
    ptr = (*headRef);
    newnode = (struct node*)malloc(sizeof(struct node));
    newnode->data = newData;
    newnode->next = NULL;
    if (*headRef == NULL)
    {
        *headRef = newnode;
         return;

    }
    while (ptr->next != NULL)
    {
        ptr = ptr->next;
    }
    ptr->next = newnode;
    return;
}

最后插入链表

1 个答案: