我想实现一个基于简单数字优先级处理意图的IntentService(source code)。具有较高优先级的意图应首先由服务处理,而不是优先级较低的意图。
Android上有没有这样做呢?如果没有,关于如何实现它的任何指针?
答案 0 :(得分:18)
根据CommonsWare的答案和Android的IntentService
source code,首次尝试实施具有优先级的意向服务。将进行广泛测试并进行相应的编辑。
public abstract class PriorityIntentService extends Service {
private final class QueueItem implements Comparable<QueueItem> {
Intent intent;
int priority;
int startId;
@Override
public int compareTo(QueueItem another) {
if (this.priority < another.priority) {
return -1;
} else if (this.priority > another.priority) {
return 1;
} else {
return (this.startId < another.startId) ? -1 : 1;
}
}
}
private final class ServiceHandler extends Handler {
public ServiceHandler(Looper looper) {
super(looper);
}
@Override
public void handleMessage(Message msg) {
try {
final QueueItem item = mQueue.take();
onHandleIntent(item.intent);
if (mQueue.isEmpty()) {
PriorityIntentService.this.stopSelf();
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
public static final String EXTRA_PRIORITY = "priority";
private String mName;
private PriorityBlockingQueue<QueueItem> mQueue;
private boolean mRedelivery;
private volatile ServiceHandler mServiceHandler;
private volatile Looper mServiceLooper;
public PriorityIntentService(String name) {
super();
mName = name;
}
@Override
public IBinder onBind(Intent intent) {
return null;
}
@Override
public void onCreate() {
super.onCreate();
HandlerThread thread = new HandlerThread("PriorityIntentService[" + mName + "]");
thread.start();
mServiceLooper = thread.getLooper();
mServiceHandler = new ServiceHandler(mServiceLooper);
mQueue = new PriorityBlockingQueue<QueueItem>();
}
@Override
public void onDestroy() {
mServiceLooper.quit();
}
protected abstract void onHandleIntent(Intent intent);
@Override
public void onStart(Intent intent, int startId) {
final QueueItem item = new QueueItem();
item.intent = intent;
item.startId = startId;
final int priority = intent.getIntExtra(EXTRA_PRIORITY, 0);
item.priority = priority;
mQueue.add(item);
mServiceHandler.sendEmptyMessage(0);
}
@Override
public int onStartCommand(Intent intent, int flags, int startId) {
onStart(intent, startId);
return mRedelivery ? START_REDELIVER_INTENT : START_NOT_STICKY;
}
public void setIntentRedelivery(boolean enabled) {
mRedelivery = enabled;
}
}
答案 1 :(得分:2)
不是真的。但是,IntentService
并不多。烹饪由PriorityIntentService
支持的PriorityBlockingQueue
,而不是Handler
+ Looper
,不应该更长。