Question

我遇到了这段代码的问题。我看到的问题是，当用户运行代码并且正确猜测或使用最大尝试次数时，while循环不会启动并允许游戏重新启动。我的想法是将计数器（尝试）重置为零并重新开始，但我只是获得了总分的退出消息。

int guess = 0;
     int attempt = 0;
     int number = new Random().nextInt(1000) + 1;
     int scorePlayer = 0; int scoreComputer = 0;
     boolean repeat;

     System.out.println("Hello and welcome to the number guessing game.");
     System.out.println("Please guess a number between 1 and 1000");


    while(repeat == true){
         do{
             Scanner scan = new Scanner(System.in);
             guess = Integer.parseInt(scan.nextLine());
             System.out.println("The number you guessed is "+guess);
             attempt++;

             if(guess == number){
                 System.out.println("Congratulations! You got it!!");
                 scorePlayer++;
                 System.out.println("Would you like to play again? [YES/NO]");
                 Scanner a = new Scanner(System.in);
                 String answer = a.nextLine().toUpperCase();
                 if (answer != "YES"){
                     //repeat = false;
                     System.out.println("Thank you for playing");
                     System.out.println("The final score is "+scorePlayer+" to you and "+scoreComputer+" to the server");
                     if (scorePlayer<scoreComputer){
                         System.out.println("Computer wins!");
                     }else{
                         System.out.println("You win!");
                     }break;
                 }else{
                     attempt = 0;
                 }
             }else if(guess < number){
                 System.out.println("That is incorrect, try a larger number");

             }else if(guess > number){
                 System.out.println("That is incorrect, try a smaller number");

             }if(attempt == 10 && guess != number){
                 System.out.println("That is the max number of guesses allowed");
                 System.out.println("The number you were looking for is "+number);
                 scoreComputer++;
                 System.out.println("Would you like to play again? [YES/NO]");
                 Scanner b = new Scanner(System.in);
                 String answer = b.nextLine().toUpperCase();
                 if (answer != "YES"){
                     //repeat = false;
                     System.out.println("Thank you for playing");
                     System.out.println("The final score is "+scorePlayer+" to you and "+scoreComputer+" to the server");
                     if (scorePlayer<scoreComputer){
                         System.out.println("Computer wins!");
                     }else{
                         System.out.println("You win!");
                     }break;
                 }else{
                     attempt = 0;
                 }
             }

         }while(guess != number || attempt == 0);
         repeat = false;
    }

Answer 1

Single＆＃34; =＆＃34;是一个赋值运算符，只需将其更改为double＆＃34; ==＆＃34;。

while(repeat == true)

Answer 2

除了ugur所说的，你可以简单地做到

while(repeat)

因为repeat是一个布尔变量（返回true或false）

Answer 3

检查您正在设置repeat=false的外部循环中的最后一行。因此，当您从内部循环break时，外部while检查重复，除了第一个之外每次都是假。

如何在数字猜测游戏中重启while循环

3 个答案: