Question

对于一个班级作业，我正在尝试制作一个数字猜谜游戏，在该游戏中，用户确定答案和猜谜次数，然后在这些有限的回合时间内猜出该数字。我应该和and运算符一起使用while循环，并且不能使用break。但是，我的问题是我不确定如何格式化程序，以便在达到最大转数时，程序不会显示提示（增大/减小），而只会告诉您迷路了/发生了什么答案是。 如果我选择最大猜测数为1，则无法正常工作。不仅打印“您输了，这个数字是__”，它还打印了一个提示。这是我最好的尝试，几乎可以完成该程序应做的所有事情。我在做什么错了？

answer = int(input("What should the answer be? "))
guesses = int(input("How many guesses? "))

guess_count = 0
guess = int(input("Guess a number: "))
guess_count += 1
if answer < guess:
    print("The number is lower than that.")
elif answer > guess:
    print("The number is higher than that")

while guess != answer and guess_count < guesses:
    guess = int(input("Guess a number: "))
    guess_count += 1
    if answer < guess:
        print("The number is lower than that.")
    elif answer > guess:
        print("The number is higher than that")

if guess_count >= guesses and guess != answer:
    print("You lose; the number was " + str(answer) + ".")
if guess == answer:
    print("You win!")

Answer 1

这样的事情呢？

answer = int(input("What should the answer be? "))
guesses = int(input("How many guesses? "))
guess_count = 1
guess_correct = False

while guess_correct is False:
    if guess_count < guesses:
        guess = int(input("Guess a number: "))
        if answer < guess:
            print("The number is lower than that.")
        elif answer > guess:
            print("The number is higher than that")
        else:  # answer == guess
            print("You win!")
            break
        guess_count += 1
    elif guess_count == guesses:
        guess = int(input("Guess a number: "))
        if guess != answer:
            print("You lose; the number was " + str(answer) + ".")
        if guess == answer:
            print("You win!")
        break

它与您的程序非常相似，但是其中有几个break语句。这告诉Python立即停止执行该循环并转到下一个代码块（在这种情况下为空）。这样，您不必等待程序评估为while循环指定的条件，然后再开始下一个循环。如果这有助于解决您的问题，请点击我的帖子中的复选标记

有限猜测的Python while循环数猜测游戏

1 个答案: