使用半胱氨酸的两点之间的距离

Question

我有一个csv文件＆＃34; f1.csv＆＃34; （没有标题）：

Index,Lattitude,Longitude
    1,52.2296756,21.0122287
    2,52.406374,16.9251681
    3,52.346374,19.9251681
    4,52.406374,16.9251681

我想计算每个索引的距离，并在另一个csv文件中附加sortest距离索引。我想要这样的输出：

Index,Lattitude,Longitude,ShortestIndex
    1,52.2296756,21.0122287,2
    2,52.406374,16.9251681,4
    3,52.346374,19.9251681,3
    4,52.406374,16.9251681,4

这里是我试过的python代码，它只计算一行的距离。

from math import sin, cos, sqrt, atan2, radians
import csv

R = 6373.0

distance=[]
with open('f1.csv', 'r') as inf:
  for l in inf:
            #for j in inf:
                e = l[:-1].split(',')
                lat2= radians(float(e[1]))
                lon2= radians(float(e[2]))
                lat1 = radians(float(52.2296756))
                lon1 = radians(float(21.0122287))
                dlon = lon2 - lon1
                dlat = lat2 - lat1
                a = sin(dlat / 2)**2 + cos(lat1) * cos(lat2) * sin(dlon / 2)**2
                c = 2 * atan2(sqrt(a), sqrt(1 - a))
                dist = R * c
                distance.append(dist)
                print (dist)
distance.sort()
print (distance)

输出是：

 0.0
278.545589351
75.0915410407
278.545589351
[0.0, 75.0915410407001, 278.54558935106695, 278.54558935106695]