javascript中数组中的最小值忽略特定元素

Question

我有一个包含3个元素的数组。

var arr = [-1,2,-1];

如何在数组中找到最小值，当我想忽略数组中的'-1'时，无论其位置如何。

var arr = [-1,1,3];     //should give 1
var arr = [-1,2,-1];    //should give 2
var arr = [1,0,-1,4,5,2];    //should give 0

Answer 1

您可以过滤值并从中获取最小值。

var array = [1, 0, -1, 4, 5, 2],
    min = Math.min(...array.filter(a => a !== -1));
    
console.log(min);

Answer 2

使用Array#reduce方法

var arr = [-1, 1, 0, -1, 4, 5, 2];

console.log(
  // iterate and comare values
  arr.reduce(function(a, b) {
    // compare the values
    return (a === null || b < a) && b > -1 ? b : a;
    // set initial value as null to avoid selecting -ve value
    // in  case all values are negative   
  }, null)
)

// with ES6 arrow function

console.log(
  arr.reduce((a, b) => (a === null || b < a) && b > -1 ? b : a, null)
)

var arr = [-1, 1, 3]; //should give 1
var arr1 = [-1, 2, -1]; //should give 2
var arr2 = [1, 0, -1, 4, 5, 2];

console.log(
  arr.reduce((a, b) => (a === null || b < a) && b > -1 ? b : a, null)
)
console.log(
  arr1.reduce((a, b) => (a === null || b < a) && b > -1 ? b : a, null)
)
console.log(
  arr2.reduce((a, b) => (a === null || b < a) && b > -1 ? b : a, null)
)

Answer 3

您是否尝试从阵列中删除负数？

const newArr = arr.filter(num => num >= 0)