简单的Android套接字编程

Question

我正在学习android套接字编程。代码如下。在第一次单击该按钮时，消息将成功发送到服务器，但是在第二次单击消息未进入服务器之后，它也没有显示任何错误。

public class MainActivity extends AppCompatActivity implements View.OnClickListener {
  private InetAddress address;
  private Button send;
  @Override
  protected void onCreate(Bundle savedInstanceState) {
      super.onCreate(savedInstanceState);
      setContentView(R.layout.activity_main);
      send = (Button) this.findViewById(R.id.Send);
      send.setOnClickListener(this);
  }
  @Override
  public void onClick(View v) {
      new Sender().execute("xxx.xxx.xx.xxx");
  }
  private class Sender extends AsyncTask<String, Void, Void> {
      private Socket socket;
      private Connector connector;
      public Sender() {}
      @Override
      protected Void doInBackground(String... params) {
          try {
              address = InetAddress.getByName(params[0]);
              socket = new Socket(address, 10001);
              connector = new Connector(socket);
              connector.write("Hello server, this is client");
          } catch (UnknownHostException e) {
              Log.d("Error", e.getLocalizedMessage());
          } catch (IOException e) {
              Log.d("Error", e.getLocalizedMessage());
          }
          return null;
      }
  }
}





public class Connector {
  private Socket socket;
  private PrintWriter writer;
  public Connector(Socket soc) {
      socket = soc;
      try {
          writer = new PrintWriter(socket.getOutputStream(), true);
      } catch (IOException e) {
          Log.d("Error", e.getLocalizedMessage());
      }
  }
  public void write(String message) {
      writer.println(message);
  }
}