我的导师建议我重新采样我的p值（许多不同的测试，每个使用不同的预测器）作为纠正可能相关的测量的多重比较的更好方法。我创建了一个包含所有p值的向量，并尝试在汽车的Boot函数中应用它，但它不起作用。
pvalues1 <- c("0.186","0.123","0.417","0.025","0.558","0.032","0.360","0.022","0.232","0.243","0.675","0.283","0.443","0.251","0.822","0.506","0.803","0.357","0.608","0.128","0.536","0.150","0.691","0.132","0.861","0.689","0.475","0.125","0.496","0.158","0.476","0.153","0.318","0.099","0.356","0.012","0.543","0.028","0.331","0.011","0.951","0.311","0.544","0.186","0.192","0.810","0.202","0.447","0.823","0.997","0.657","0.517","0.345","0.427","0.857","0.578","0.233","0.0004","0.775","0.012","0.538","0.118","0.491","0.004","0.003","0.0005","0.011","0.007","0.148","0.083","0.003","0.002","0.837","0.345","0.466","0.015","0.184","0.023","0.680,"0.017")
pvalues2 <- as.numeric(pvalues1)
output <- Boot(pvalues2, R=1999)
关于我如何做到这一点的任何建议？