JPA为EmbeddedId

Question

在JPABootApplication over Hibernate中我需要定义一个带有2个PK的表 我将另一个类定义为PK并用@Embeddable注释它 在实体类中，我有PK的成员用@EmbeddableId进行了分配。 这是代码：

帐户：

package demo;

import javax.persistence.EmbeddedId;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Table(name="ACCOUNTS")
public class Account {

    @EmbeddedId
    private AccountId accountId;
    private String upassword;
    private String fName;
    private String lName;
    private boolean isManager;

    public Account() {
        // TODO Auto-generated constructor stub
    }


    public Account(AccountId accountId, String upassword, String fName, String lName, boolean isManager) {
        super();
        this.accountId = accountId;
        this.upassword = upassword;
        this.fName = fName;
        this.lName = lName;
        this.isManager = isManager;
    }


    public AccountId getAccountId() {
        return accountId;
    }


    public void setAccountId(AccountId accountId) {
        this.accountId = accountId;
    }


    public String getUpassword() {
        return  upassword;
    }
    public void setUpassword(String upassword) {
        this.upassword = upassword;
    }


    public String getfName() {
        return fName;
    }
    public void setfName(String fName) {
        this.fName = fName;
    }


    public String getlName() {
        return lName;
    }
    public void setlName(String lName) {
        this.lName = lName;
    }


    public boolean isManager() {
        return isManager;
    }
    public void setManager(boolean isManager) {
        this.isManager = isManager;
    }



}

ACCOUNTID：

package demo;

import java.io.Serializable;

import javax.persistence.Embeddable;
import javax.persistence.GeneratedValue;

@Embeddable
public class AccountId implements Serializable {
    private Long accId;
    private String uName;

    public AccountId() {
        // TODO Auto-generated constructor stub
    }

    @GeneratedValue
    public Long getAccId() {
        return accId;
    }
    public void setAccId(Long accId) {
        this.accId = accId;
    }
    public String getuName() {
        return uName;
    }
    public void setuName(String uName) {
        this.uName = uName;
    }

    @Override
    public int hashCode() {
        final int prime = 31;
        int result = 1;
        result = prime * result + ((accId == null) ? 0 : accId.hashCode());
        result = prime * result + ((uName == null) ? 0 : uName.hashCode());
        return result;
    }

    @Override
    public boolean equals(Object obj) {
        if (this == obj)
            return true;
        if (obj == null)
            return false;
        if (getClass() != obj.getClass())
            return false;
        AccountId other = (AccountId) obj;
        if (accId == null) {
            if (other.accId != null)
                return false;
        } else if (!accId.equals(other.accId))
            return false;
        if (uName == null) {
            if (other.uName != null)
                return false;
        } else if (!uName.equals(other.uName))
            return false;
        return true;
    }


}

现在，我正在尝试向帐户添加帐户：     包演示;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.boot.CommandLineRunner;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.context.annotation.ComponentScan;


@SpringBootApplication
@ComponentScan({"demo" })
public class TestApplication implements CommandLineRunner{

    @Autowired
    private AccountManager accountManager;


    public static void main(String[] args) {
        SpringApplication.run(TestApplication.class, args);
    }

    @Override
    public void run(String... args) throws Exception {

        AccountId aid1 = new AccountId();
        aid1.setuName("AAAA");
        Account a1 = new Account(aid1, "0212", "KKKK", "SSS", false);
        Long a1id = accountManager.addNewAccount(a1);
        System.err.println(a1id + ") " + a1);


    }
}

然后我因插入Null而得到Exception。我希望将accId设为AutoGenerated（有@GeneratedValue注释）：

  

2017-06-12 20：44：18.440 WARN 7200 --- [main] o.h.engine.jdbc.spi.SqlExceptionHelper：SQL错误：515，SQLState：23000   2017-06-12 20：44：18.441 ERROR 7200 --- [main] ohengine.jdbc.spi.SqlExceptionHelper：无法将值NULL插入列＆quot; acc_id＆＃39;，table＆＃39; trading。 dbo.accounts11＆＃39 ;;列不允许空值。 INSERT失败。   2017-06-12 20：44：18.442 INFO 7200 --- [main] o.h.e.j.b.internal.AbstractBatchImpl：HHH000010：在批量发布时它仍然包含JDBC语句   2017-06-12 20：44：18.447 INFO 7200 --- [主要] utoConfigurationReportLoggingInitializer：

我怎样才能让它发挥作用？