从xlsx文件调用我得到属性错误但我没有在创建数据帧pandas时

Question

我正在尝试使用两个数据帧：

df1 = df.copy()

df1['emails'] = df1.emails.apply(lambda x: ','.join(set(map(str.strip, x.split(','))) - set(blacklisted.email)))

df1 = df1[df1.emails != '']

当我自己创建具有相同信息的数据帧时，它返回相同的数据类型;例如，如果我创建一个如下所示的数据框：

blacklisted=pd.DataFrame(columns=['email'],
                data=[['smith.john@hotmail.com'],['earl.bob@jpmorgan.com'],['banana.star@csu.edu'], ['london.flag@wholefoods.com'], 
                      ['soft.pretzel@utz.com']])

blacklisted.head()

 email
0   smith.john@hotmail.com
1   earl.bob@jpmorgan.com
2   banana.star@csu.edu
3   london.flag@wholefoods.com
4   soft.pretzel@utz.com

和另一个看起来像这样的数据框：

df=pd.DataFrame(columns=['customerId','full name','emails'],
                data=[['208863338', 'Brit Spear', 'star.shine@cw.com'],['086423367', 'Justin Bob', 'bob.love@gem.com,ruby.blue@yahoo.com'],['902626998', 'White Ice', 'iceblue@starr.com,ice@msn.com'], ['1000826799', 'Bear Lou', 'lou.bear@visa.com'], 
                      ['1609813339',   'Ariel Do', 'ariel.d@fire.com, ariel@yahoo.com']])
print(df)



customerId      full name       emails
0   208863338   Brit Spear  star.shine@cw.com
1   086423367   Justin Bob  bob.love@gem.com,ruby.blue@yahoo.com
2   902626998   White Ice   iceblue@starr.com,ice@msn.com
3   1000826799  Bear Lou    lou.bear@visa.com
4   1609813339  Ariel Do    ariel.d@fire.com, ariel@yahoo.com

上面的代码有效但当我尝试从两个文件调用相同的信息而不是使用这样的代码：

blacklisted = df1 = pd.read_excel(r'C:/Users/Administrator/Documents/sfiq/blacklisted.xlsx')
df = pd.read_excel(r'C:/Users/Administrator/Documents/customers.xlsx')

与我在上面创建的两个数据帧完全相同的信息它不起作用，我得到一个属性错误：

df1['emails'] = df1.emails.apply(lambda x: ','.join(set(map(str.strip, x.split(','))) - set(blacklisted.email)))

返回的错误是：

---------------------------------------------------------------------------
AttributeError                            Traceback (most recent call last)
<ipython-input-22-439d1f152f33> in <module>()
----> 1 df1['emails'] = df1.emails.apply(lambda x: ','.join(set(map(str.strip, x.split(','))) - set(blacklisted.email)))

C:\Program Files\Anaconda3\lib\site-packages\pandas\core\series.py in apply(self, func, convert_dtype, args, **kwds)
   2218         else:
   2219             values = self.asobject
-> 2220             mapped = lib.map_infer(values, f, convert=convert_dtype)
   2221 
   2222         if len(mapped) and isinstance(mapped[0], Series):

pandas\src\inference.pyx in pandas.lib.map_infer (pandas\lib.c:62658)()

<ipython-input-22-439d1f152f33> in <lambda>(x)
----> 1 df1['emails'] = df1.emails.apply(lambda x: ','.join(set(map(str.strip, x.split(','))) - set(blacklisted.email)))

AttributeError: 'float' object has no attribute 'split'

Answer 1

假设你有：

在blacklisted.xlsx：

在customers.xlsx：

在应用此功能之前使用astype：

blacklisted = pd.read_excel(r'blacklisted.xlsx')
df = pd.read_excel(r'customers.xlsx')
df['emails'] = df.emails.astype(str).apply(lambda x: ','.join(set(map(str.strip, x.split(','))) - set(blacklisted.email)))
df

df将是：

    customerId  full name   emails
0   208863338   Brit Spear  star.shine@cw.com
1   86423367    Justin Bob  ruby.blue@yahoo.com,bob.love@gem.com
2   902626998   White Ice   ice@msn.com,iceblue@starr.com
3   1000826799  Bear Lou    lou.bear@visa.com
4   1609813339  Ariel Do    ariel@yahoo.com,ariel.d@fire.com