在我的网站中,用户使用访问令牌获取自己的密码并在我的网站中提交该代码,并且从这个代码我只想在php的帮助下获取访问令牌... 检查此 ScreenShoot ss.jpg
访问令牌示例 {"session_key":"5.TVJlCXvhgqdhpA.1497109242.26-100007001746590","uid":100007001746590,"secret":"80cc3dc2ba89e635dcf84b41d6efcc38","access_token":"EAAAAAYsX7TsBAEa6qMaCj1qCgnOKFHBcfu76C6PrUdK1LnIh39jmabZAdVWmQLO3Ol64ZCXY4388DBfUwksxONGXE5dUY0mK9M07aszl5Qvs8ccqQ39xLEsK2gc1RUJQ0Kqy1ror7R8EPHZCX6pOzX0o4oQAJ1kOq8Oz0n0GysK64ebCsDEokwG36j1awnYaDoJPvOn2AZDZD","machine_id":"-hI8WaLcNeEVUSPuxcEpmhQU","confirmed":true}
我还尝试通过分离所有这些代码来分隔访问令牌,但这实际上不起作用
这是我的php脚本
if(isset($_POST['submit'])) {
$token2 = $_POST['token'];
if(preg_match("'access_token=(.*?)&expires_in='", $token2, $matches)){
$token = $matches[1];
}
else{
$token = $token2;
}
$extend = get_html("https://graph.facebook.com/me/permissions?access_token=" . $token);
如何做到这一点,并提前感谢
答案 0 :(得分:1)
请尝试使用php将此json解析为数组,然后您可以收集所需的令牌属性并继续验证流程。此解决方案有一个相关链接:How to convert JSON string to array
有一个基本的例子:
$your_submit_data = '{"session_key":"5.TVJlCXvhgqdhpA.1497109242.26-100007001746590","uid":100007001746590,"secret":"80cc3dc2ba89e635dcf84b41d6efcc38","access_token":"EAAAAAYsX7TsBAEa6qMaCj1qCgnOKFHBcfu76C6PrUdK1LnIh39jmabZAdVWmQLO3Ol64ZCXY4388DBfUwksxONGXE5dUY0mK9M07aszl5Qvs8ccqQ39xLEsK2gc1RUJQ0Kqy1ror7R8EPHZCX6pOzX0o4oQAJ1kOq8Oz0n0GysK64ebCsDEokwG36j1awnYaDoJPvOn2AZDZD","machine_id":"-hI8WaLcNeEVUSPuxcEpmhQU","confirmed":true}';
$your_array = json_decode($your_submit_data, TRUE);
echo($your_array['access_token']);
最佳,
答案 1 :(得分:0)
您可以使用此代码仅从JSON代码中获取access_token
if(isset($_POST['submit'])) {
$token2 = $_POST['token'];
$obj = json_decode($token2);
echo "Access Token is: <br />". $obj->{'access_token'}; // You can remove it or use this value
$token = $obj->{'access_token'};
$extend = get_html("https://graph.facebook.com/me/permissions?access_token=" . $token);
}