Question

如何用“，”拆分字符串除了python中的某些字符之间？我的数据如下：

('00012+1357','LSC   2','Aa,Ab',2014,2014,   2,185,185,  0.2,  0.2,10.7,13.1,'M0.5',+019,+135,NULL,NULL,NULL,NULL,'000113.19+135830.3')

我需要将它们拆分为“，”除了'Aa，Ab'。

结果应为：

("00012+1357" "LSC   2" "Aa,Ab" "2014" "2014" "2" "185" "185" "0.2"  "0.2" "10.7" "13.1" "M0.5" "+019" "+135" "NULL" "NULL" "NULL" "NULL" "000113.19+135830.3")

你知道怎么做吗？

Answer 1

看来你正在寻找''.join（）：

the_string = ('00012+1357','LSC   2','Aa,Ab',2014,2014,   2,185,185,  0.2,  0.2,10.7,13.1,'M0.5', 19, 135, 'NULL','NULL','NULL','NULL','000113.19+135830.3')

the_string = map(str, the_string)

new_string = (' '.join(i for i in the_string))

Answer 2

您似乎正在尝试解析CSV数据。 csv模块应该足够，并且能够处理所有这些边缘情况。

Answer 3

我会尝试一些代码。如果字符串在needle之外，则按quotes拆分字符串。假设needle和quotes都是一个字符长。

#!python3

def splitExceptBetween(istr, needle, quotes):
    inside = -1
    res = []
    oldt = 0
    for index, letter in enumerate(istr):
        if letter==quotes:
            inside = -inside
        elif letter==needle and inside == -1:
            res.append(istr[oldt:index])
            oldt = index+1
    if oldt<len(istr):
        res.append(istr[oldt:])
    return res

istr = "as'das'd.asdas'd.a'sdas.drth..rt'h.r'th.'"
print(splitExceptBetween(istr, ".", "'"))
istr = "00012+1357,LSC   2,'Aa,Ab',2014,2014,   2,185,185,  0.2,  0.2,10.7,13.1,M0.5,+019,+135,NULL,NULL,NULL,NULL,000113.19+135830.3"
print(splitExceptBetween(istr, ",", "'"))

除了python中的某些字符之外，如何用“，”拆分字符串？

3 个答案: