Question

您好我已阅读使用正则表达式但我无法理解如何使用它。

我想拆分一个字符串来制作一个列表，按空格分割，除非用##或引号＆＃34包围; ＆＃34;

values = '2 #room 2.# 5 1 -1 -1'

或values = '2 "room 2." 5 1 -1 -1'

只使用split（）会导致：

['2', '#room', '2.#', '5', '1', '-1', '-1']

我希望输出没有＃的房间名称，并且因为空间而没有分开：

['2', 'room 2.', '5', '1', '-1', '-1']

Answer 1

您可以执行以下操作（将＃替换为“然后使用shelex拆分）

import shlex
values = '2 #room 2.# 5 1 -1 -1'
print(shlex.split(values.replace('#','"')))

输出

['2', 'room 2.', '5', '1', '-1', '-1']

基于 Casimir et Hippolyte 的精彩观察，请参阅评论

如果假设值为

 values = '2 #"room 2."# 5 1 -1 -1'

然后该做什么。解决方案是让字符串简单替换＃“和”＃to just“

import shlex
values = '2 #"room 2."# 5 1 -1 -1'

val=values.replace('#"','"')
print(shlex.split(val.replace('"#','"')))

输出

['2', 'room 2.', '5', '1', '-1', '-1']

Answer 2

不使用re.split描述分隔符，而是使用re.findall并描述项目：

re.findall(r'(?<=")[^"]*(?=")|(?<=#)[^#]*(?=#)|[^\s"#]+', values)

Answer 3

您可以使用regexp

public void getLocation() {
    try {
        _locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
        isGPSEnabled = _locationManager.isProviderEnabled(_locationManager.GPS_PROVIDER);
        isNetworkEnabled = _locationManager.isProviderEnabled(_locationManager.NETWORK_PROVIDER);

        if (_locationManager.getAllProviders().contains(LocationManager.GPS_PROVIDER))
            if (ActivityCompat.checkSelfPermission(this, android.Manifest.permission.ACCESS_FINE_LOCATION) != PackageManager.PERMISSION_GRANTED && ActivityCompat.checkSelfPermission(this, android.Manifest.permission.ACCESS_COARSE_LOCATION) != PackageManager.PERMISSION_GRANTED) {
                return;
            }_locationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER, 0, 0, this);

        if (_locationManager.getAllProviders().contains(LocationManager.NETWORK_PROVIDER))
            _locationManager.requestLocationUpdates(LocationManager.NETWORK_PROVIDER, 0, 0, this);

        // Ask for update
        Location mobileLocation = _locationManager.getLastKnownLocation(LocationManager.GPS_PROVIDER);
        if (mobileLocation != null) {
            onLocationChanged(mobileLocation);
        }
        Location netLocation = _locationManager.getLastKnownLocation(LocationManager.NETWORK_PROVIDER);
        if (netLocation != null) {
            onLocationChanged(netLocation);
        }

    } catch (Exception e) {
        e.printStackTrace();
    }
}

@Override
public void onLocationChanged(Location userLocation) {

    if (userLocation == null) {
        Log.e(TAG, "NO Internet");
        return;
    }

    _longitude = userLocation.getLongitude();

    _latitude = userLocation.getLatitude();

    if (marker != null) {
        marker.remove();
    }

    marker = mMap.addMarker(new MarkerOptions().position(new LatLng(_latitude, _longitude)).title("I'm Here"));

    String cityName = null;
    Geocoder gcd = new Geocoder(getBaseContext(), Locale.getDefault());
    List<Address> addresses;

    try {
        addresses = gcd.getFromLocation(userLocation.getLatitude(), userLocation.getLongitude(), 1);
        if (addresses.size() > 0)
            cityName = addresses.get(0).getLocality();
    } catch (IOException e) {
        e.printStackTrace();
    }

    String fullLocation = "Longitude : " + userLocation.getLongitude() + "\nLatitude : " + userLocation.getLatitude() + "\n\nMy Current City is: " + cityName;
    Log.e(TAG, "location : " + fullLocation);

}

参考：Split Strings with Multiple Delimiters?

如何用空格分割字符串，除非用##或＆＃34括起来; ＆＃34;

3 个答案: