提高logging.warning上的异常

Question

我想暂时让logging.warning次调用引发异常，而不是打印并继续。我怎么能这样做？

import logging
logging.warning("Foo") # Should raise exception
logging.info("Bar") # Should not raise exception

Answer 1

当您启动日志记录更改警告调用时

def warning(self, message, *args, **kws):
    if self.isEnabledFor(logging.WARNING):
        self._log(logging.WARNING, message, args, **kws)
        raise Exception(message)

logging.Logger.warning = warning