我有一个包含25个日期列的表。现在我正在使用PHP构建应用程序，并且必须显示基于月份和年份的摘要。我已经提到了Source表格布局和下面的预期汇总表。
此处Django==1.8.6
Django-Select2==4.3.1
Pillow==3.0.0
South==1.0.2
Unidecode==0.04.18
YURL==0.13
aldryn-apphooks-config==0.2.6
aldryn-boilerplates==0.7.3
aldryn-categories==1.0.1
aldryn-common==1.0.0
aldryn-newsblog==1.0.9
aldryn-people==1.1.2
aldryn-reversion==1.0.1
aldryn-translation-tools==0.2.1
argparse==1.4.0
backport-collections==0.1
cmsplugin-filer==1.0.0
dj-database-url==0.3.0
django-admin-sortable==1.8.4
django-appconf==1.0.1
django-appdata==0.1.4
django-autoslug==1.8.0
django-ckeditor-filebrowser-filer==0.1.1
django-classy-tags==0.6.2
django-cms==3.1.3
django-durationfield==0.5.2
django-easy-select2==1.3
django-filer==1.0.2
django-mptt==0.7.4
django-parler==1.5.1
django-phonenumber-field==0.7.2
django-polymorphic==0.7.2
django-reversion==1.8.7
django-sekizai==0.8.2
django-sortedm2m==1.3.2
django-taggit==0.17.3
django-treebeard==3.0
djangocms-admin-style==1.0.5
djangocms-column==1.5
djangocms-file==0.1
djangocms-flash==0.2.0
djangocms-googlemap==0.3
djangocms-inherit==0.1
djangocms-installer==0.7.9
djangocms-link==1.6.2
djangocms-picture==0.1
djangocms-style==1.5
djangocms-teaser==0.1
djangocms-text-ckeditor==2.7.0
djangocms-video==0.1
easy-thumbnails==2.2.1
gunicorn==19.4.3
html5lib==0.9999999
lxml==3.5.0
phonenumbers==7.1.1
python-dateutil==2.4.2
python-slugify==1.1.4
pytz==2015.7
simplejson==3.8.0
six==1.10.0
tzlocal==1.2
vobject==0.6.6
wheel==0.24.0
wsgiref==0.1.2
代表每一行。源表ID将在摘要表中使用。摘要表将每年创建。我需要一些帮助来准备这个汇总表。在这里我想提一下，我将在源表上有大约30K行。
来源表：
ID汇总表
ID | DATE 1 | DATE 2 | DATE 3
--------------------------------------------------
1 | 2017-01-14 | 2017-01-19 | 2017-01-25
2 | | 2017-03-19 | 2017-03-25
3 | 2017-03-15 | | 2017-05-25
4 | 2017-04-24 | 2017-05-19 |
5 | 2017-04-10 | 2017-06-19 | 2017-07-25
6 | 2017-05-11 | 2017-06-19 | 2017-08-25
答案 0 :(得分：3)
您需要取消数据并重新聚合。查询的结构是：
select id, year(date) as yyyy,
sum( month(date) = 1 ) as Jan,
sum( month(date) = 2 ) as Feb,
. . .
sum( month(date) = 12 ) as Dec
from ((select id, date1 as date from source) union all
(select id, date2 as date from source) union all
. . .
(select id, date25 as date from source)
) d
where date is not null
group by id, year(date)
order by id, year(date);
. . .表示填空。