我试图拉动所有少于4个订单的客户 过去3个月在Google BigQuery中。
SELECT a.user_id, b.refer_by, FROM water_db.tb_order a INNER JOIN
water_auth.tb_users b ON a.user_id = b.user_id WHERE ( SELECT
user_id FROM
water_db.tb_order GROUP BY
user_id HAVING
COUNT(DISTINCT(a.user_id <= 4))) AND status = 3 AND DATE(a.order_date) >=
'2017-02-15' AND DATE(a.order_date) <= '2017-05-15';------
答案 0 :(得分:0)
我猜测每次将记录添加到表中它都等同于订单,但是类似于:
SELECT
a.userid, b.refer_by
FROM water_db.tb_order a
INNER JOIN water_auth.tb_users b ON a.user_id = b.user_id
WHERE
(COUNT(userid) < 4)
and
DATE_ADD(MONTH, -4, a.order_date)
日期功能可能会有所不同,因为我不能100%确定Google Big Query中的内容
答案 1 :(得分:0)
我认为解决此问题的最佳方法是从用户表中进行选择,这样您就不需要对ID进行重复数据删除,只是将条件表达为WHERE
子句的一部分。这应该有助于您入门:
#standardSQL
SELECT
user_id,
refer_by
FROM water_db.tb_users
WHERE (
SELECT COUNT(*)
FROM water_db.tb_order
WHERE tb_users.user_id = tb_order.user_id AND
status = 3 AND
DATE(order_date) BETWEEN '2017-02-15' AND '2017-05-15'
) <= 4;
在此查询中,连接表示为涉及两个表的相关子查询。您可以使用此查询使用示例数据进行尝试:
#standardSQL
WITH tb_users AS (
SELECT 1 AS user_id, 'foo@bar.com' AS refer_by UNION ALL
SELECT 2, 'a@b.com' UNION ALL
SELECT 3, 'baz@baz.com'
),
tb_order AS (
SELECT 1 AS user_id, TIMESTAMP '2017-04-12' AS order_date, 3 AS status UNION ALL
SELECT 2, TIMESTAMP '2017-05-03', 3 UNION ALL
SELECT 1, TIMESTAMP '2017-03-13', 3 UNION ALL
SELECT 1, TIMESTAMP '2017-02-28', 3 UNION ALL
SELECT 2, TIMESTAMP '2017-05-06', 3 UNION ALL
SELECT 1, TIMESTAMP '2017-05-01', 3 UNION ALL
SELECT 1, TIMESTAMP '2017-05-02', 3
)
SELECT
user_id,
refer_by
FROM tb_users
WHERE (
SELECT COUNT(*)
FROM tb_order
WHERE tb_users.user_id = tb_order.user_id AND
status = 3 AND
DATE(order_date) BETWEEN
'2017-02-15' AND '2017-05-15'
) <= 4;