Question

我有多个键和一个数组，一次只存在一个键，但我不知道哪个键存在。

我的问题是我必须获得数组中存在的那个键的值，但我不想在个别键上使用loop或isset，我想知道是否有任何存在内置PHP函数，我可以通过它实现此解决方案吗？

$keys = array("key1","key2","key3");
$data= array("mykey"=>"myval","mykey2"=>"myval2","key2"=>"key2val");

$val = isset($data["key1"])?1:(isset($data["key2"])?2:(isset($data["key3"])?3:0));//i dont want to use this or any loop

Answer 1

以下是您的解决方案：

 $keys = array("key1","key2","key3");
 $data= array("mykey"=>"myval","mykey2"=>"myval2","key2"=>"key2val");

print_r (current(array_intersect_key($data, array_flip($keys))));

我认为你需要使用循环，因为这将是一个更好的解决方案

$keys = array("key1","key2","key3");
$data= array("mykey"=>"myval","mykey2"=>"myval2","key2"=>"key2val");

foreach($data as $key=>$value)
{
  if(in_array($key,$keys))
  {
    // your logic
  }
}

Answer 2

走他们的路口：

// Flip is needed for [key1 => 0, ...] representation
$list = array_intersect_key(array_flip($keys), $data);
// Check existence 
if ($list) {
    // You need the value, started from 1 (instead of zero)
    $val = 1 + current($list);
} else {
    $val = 0;
}

Answer 3

这是一个班轮。但是你能在一个月后解释一下吗？

$keys = array("key1","key2","key3");
$data = array("mykey"=>"myval","mykey2"=>"myval2","key2"=>"key2val");

print_r( array_intersect($keys, array_keys($data)) );

// Output:
Array
(
    [1] => key2
)

如何在数组中搜索多个键并返回第一个找到的值？

3 个答案: