Question

我有这个数组：

Array
(
    [0] => Array
        (
            [id] => 15bw83nfo3wg4
            [date] => 2019-01-01
            [d_c] => D
            [D] => 76181734.95
            [C] => 0.00
        )

    [1] => Array
        (
            [id] => 15byrr7fo3wg4
            [date] => 2019-01-02
            [d_c] => D
            [D] => 4000000.00
            [C] => 0.00
        )

    [2] => Array
        (
            [id] => 15bzwubfo3wg4
            [date] => 2019-01-02
            [d_c] => K
            [D] => 0.00
            [C] => 1585500.00
        )

    [3] => Array
        (
            [id] => 15c0vlvfo3wg4
            [date] => 2019-01-02
            [d_c] => K
            [D] => 0.00
            [C] => 10000000.00

如何在以日期作为参数值的数组中搜索并返回包含参数值的 ALL 数组？

我已经尝试过了：

$date = '2019-01-02';
$key = array_search($date, array_column($data, 'date'));
$result = $data[$key];

但是我得到的结果仅仅是：

[1] => Array
     (
        [id] => 15byrr7fo3wg4
        [date] => 2019-01-02
        [d_c] => D
        [D] => 4000000.00
        [C] => 0.00
     )

Answer 1

使用array_filter函数

$result = array_filter($data, function($x) use ($date) { return $x['date'] == $date; });

Answer 2

您只会得到一个结果，因为您的$key变量仅返回找到的第一个元素，要获取多个，您需要使用：

array_keys(array_column($array, 'date'), "2019-01-02")

这将返回包含您要查找的数组中的键的键列表。

然后您可以遍历它们：

$array = [["id" => 1, "date" => "2019-01-02"],["id" => 2, "date" => "2019-01-03"],["id" => 3, "date" => "2019-01-02"],["id" => 4, "date" => "2019-01-05"]];

$date = '2019-01-02';

$keys = array_keys(array_column($array, 'date'), "2019-01-02");

$results = [];

foreach ($keys as $key) {
    $results[] = $array[$key];
}

var_dump($results);

数组多维搜索返回所有多个键

2 个答案: