Question

在我的代码中点击异常，以便在URI上使用JSON

public static String processRestResponse(String language){
    URI uri = null;
    JSONTokener tokener = null;
    try {
        uri = new URI("https://api.github.com/search/repositories?q=language:Java");
        URL url = uri.toURL();
        InputStream inputStream = url.openStream();
        tokener = new JSONTokener(inputStream.toString());
        JSONObject root = new JSONObject(tokener);
    } catch (Exception e) {
        e.printStackTrace();
    }

例外情况如下......

org.json.JSONException: A JSONObject text must begin with '{' at character 1
at org.json.JSONTokener.syntaxError(JSONTokener.java:410)
at org.json.JSONObject.<init>(JSONObject.java:179)
at Assignment1.processRestResponse(Assignment1.java:48)
at Assignment1.main(Assignment1.java:108)

我可以选择哪种方法适合吗？

Answer 1

确保使用正确的字符集正确读取InputStream，例如：

StringBuilder textBuilder = new StringBuilder();
try (Reader reader = new BufferedReader(new InputStreamReader(inputStream, Charset.forName(StandardCharsets.UTF_8.name())))) {
    int c = 0;
    while ((c = reader.read()) != -1) {
        textBuilder.append((char) c);
    }
}

之后你可以使用它：

tokener = new JSONTokener(textBuilder.toString());
JSONObject root = new JSONObject(tokener);

JSONTokener：JSONObject文本必须以“{”开头

1 个答案: