Question

我希望获得＆＃34; name＆＃34;的价值来自以下机构：

$collection->find(array('age_premium.age'=>'65'));

我尝试过以下代码：

[
  {
    "name": "ENTITY_CHANNELS",
    "description": "The list of channels use to deliver through.",
    "metadata": "{}"
  },
  {
    "name": "INTAKE_SFTP",
    "description": null,
    "metadata": "{\n  \"fields\":[\n    {\n      
\"field_name\":\"user_uat\",\n      \"field_type\":\"string\",\n      
\"field_required\":true, \n\t  \"field_description\": \"UAT User name\"\n    
},\n    {\n      \"field_name\":\"user_prod\",\n      
\"field_type\":\"string\",\n      \"field_required\":false, \n\t  
\"field_description\": \"Production User name\"\n    },\n    {\n      
\"field_name\":\"folder\",\n      \"field_type\":\"string\",\n      
\"field_required\":true, \n\t  \"field_description\": \"Folder\"\n    },\n    
{\n      \"field_name\":\"address_UAT\",\n      \"field_type\":\"string\",\n      
\"field_required\":true, \n\t  \"field_description\": \"UAT address\"\n    
},\n    {\n      \"field_name\":\"address_PROD\",\n      
\"field_type\":\"string\",\n      \"field_required\":false, \n\t  
\"field_description\": \"Production address\"\n    },\n    {\n      
\"field_name\":\"port\",\n      \"field_type\":\"integer\",\n      
\"field_required\":true, \n\t  \"field_description\": \"Port\"\n    },\n    
{\n      \"field_name\":\"protocol_version\",\n      
\"field_type\":\"version\",\n      \"field_required\":false, \n\t  
\"field_description\": \"Protocol version\"\n    }\n  ]\n}"
  }
]

但我一直在收到错误：JSONObject文本必须以＆＃39; {＆＃39;错误。我想提取＆＃34; name＆＃34;的价值。有人能帮助我吗？

Answer 1

谢谢大家的意见。我意识到我的错误是什么。我用过：

String settingsTypeData = response.body().toString();

以下代码将解决我的问题：

String settingsTypeData = response.body().string();
    JSONArray settingsTypeArray = new JSONArray(settingsTypeData);

    String firstSettingType = settingsTypeArray.getJSONObject(0).getString("name");
    Assert.assertEquals(firstSettingType, "ENTITY_CHANNELS");

    String secondSettingType = settingsTypeArray.getJSONObject(1).getString("name");
    Assert.assertEquals(secondSettingType, "INTAKE_SFTP");

Answer 2

使用JSONArray代替JSONObject，因为上面的整个json是JSONArray。然后迭代此JSONArray并从每个JSONObject

获取名称

   String settingsTypeData = response.body().toString();
   try {
        JSONArray settingsTypeArray = new JSONArray(settingsTypeData);
        for(int i=0;i<settingsTypeArray.length();i++){
            String name = settingsTypeArray.getJSONObject(i).getString("name");
            Log.d(TAG, "onActivityResult: name = "+name);
        }
    } catch (JSONException jex){
        jex.printStackTrace();
    }

JSONObject文本必须以＆＃39; {＆＃39;错误

2 个答案: