我想知道二进制图像和圆之间的值交叉

Question

clc
clear
a = imread('004_1.bmp');
I2 = imcrop(a,[80 17 101 180]);
[i,j]=size(I2);    


x_hist=sum(I2,1);
y_hist=(sum(I2,2))';

x=1:j ; y=1:i;
centx=sum(x.*x_hist)/sum(x_hist)
centy=sum(y.*y_hist)/sum(y_hist)


BW = edge(I2,'Canny',0.329);
bw2 = imcomplement(BW);
circle = int32([centx,centy,40]);
shapeInserter = vision.ShapeInserter('Fill',false);
release(shapeInserter);
set(shapeInserter,'Shape','Circles');
K = step(shapeInserter,bw2,circle);


figure, imshow(K)

我有这个程序，我想知道圆和二进制图像之间的交叉点的价值。如果有人知道如何找到价值？

Answer 1

您可以使用find获取所需图像的索引，如下所示：

bwCircle = step(shapeInserter,true(size(bw2)),circle); % construct binary image of circle only
[i, j] = find ((bw2 | bwCircle) == 0); % find the indexes of the intersection between the binary image and the circle

figure 
imshow(bw2 & bwCircle) % plot the combination of both images
hold on
plot(j, i, 'r*') % plot the intersection points