Question

所以我正在创建一个小型网站，并希望选择一个mysql行，其中行中的idu与刚刚登录到站点的用户的会话ID相同，该会话在网站的其他页面上运行良好但我对此无能为力，请参阅下面的代码

<?php
include('solutions/session.php');
$id ='';
$id= $_SESSION['id'];
$page_name = 'settings';
$con=mysqli_connect("localhost","root","usbw","company");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM payment WHERE idu='$id'");

echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";

while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['wallet'] . "</td>";
echo "<td>" . $row['amount'] . "</td>";
echo "</tr>";
}
echo "</table>";

mysqli_close($con);
?>

和session.php看起来像这样

<?php
$connection = mysql_connect("localhost", "root", "usbw");
$db         = mysql_select_db("company", $connection);
session_start();
$user_check    = $_SESSION['login_user'];
$ses_sql       = mysql_query("select username from wallet where username='$user_check'", $connection);
$row           = mysql_fetch_assoc($ses_sql);
$login_session = $row['username'];
if (!isset($login_session)) {
    header("location: index.php");
  mysql_close($connection);
}
?>

Answer 1

首先，您的 session.php 文件代码无法正常工作，因为您使用的是mysql_query并且还传递了导致错误使用的连接 mysqli_query（）

$ses_sql = mysqli_query($con,"select username from wallet where username='".$id."' ");
$row = mysqli_fetch_assoc($ses_sql);
//then set your session variable most imortant is id which is usefull
$_SESSION['id'] = $row["id"];

其余的事情都很好

Answer 2

尝试替换此行：

$result = mysqli_query($con,"SELECT * FROM payment WHERE idu='$id'");

这一个：

$result = mysqli_query($con,"SELECT * FROM payment WHERE idu=".$id);

如何选择mysql行，其中idu与SESSION id相同

2 个答案: