我正在使用angular-tree-component(https://angular2-tree.readme.io)在Angular2应用程序中显示一个树。
我需要让用户能够选择树中的任何节点并将其删除。这应该删除所选节点及其所有子节点(如果它是叶子节点,那么只是节点)。用户完成后,已修剪的树将被发送到服务器并保存在那里。
在下面的示例中,用户选择节点1-2'并单击“删除”。这将删除节点1-2,节点1'和节点2'节点2'从视图和底层Javascript对象更新。然后,用户可以单击另一个按钮(例如,保存)以将更新的对象保存在服务器上。
为了实现这一点,我编写了以下代码,单击“删除”按钮即可调用该代码。我存储所选节点的id,然后遍历整个树以找到该id。当id匹配时,我使用'删除'要删除的关键字' id'和'文字'。但是,删除儿童'不起作用。
deleteSelectedNode() {
//Get the node which was selected by the user
let nodeToDelete: TreeNode = this.myService.getActiveNode();
//id will be unique, can be used to identify the node
let idToDelete = nodeToDelete.data.id;
this.traverseTree(this.nodes[0], idToDelete);
}
traverseTree(obj, idToDelete: string) {
for (var k in obj) {
if (typeof obj[k] == "object" && obj[k] !== null) {
this.traverseTree(obj[k], idToDelete);
}
else {
if (k === 'id') {
let id = obj[k];
if (id === idToDelete) {
console.log('ID Matched ' + id);
delete obj['id'];
delete obj['text'];
delete obj['children'];
break;
}
}
}
}
}
下面是渲染树的JSON。
{
"children": [
{
"children": [
{
"text": "Node 1",
"id": "A493"
},
{
"text": "Node 2",
"id": "A494"
}
],
"text": "Node 1-2",
"id": "A491"
},
{
"children": [
{
"children": [
{
"text": "Node 3",
"id": "A5ab"
},
{
"text": "Node 4",
"id": "A5ac"
},
{
"text": "Node 5",
"id": "A5ad"
},
{
"text": "Node 6",
"id": "A5ae"
},
{
"text": "Node 7",
"id": "A5af"
},
{
"text": "Node 8",
"id": "A5b0"
},
{
"text": "Node 9",
"id": "A5b1"
},
{
"text": "Node 10",
"id": "A5b2"
},
{
"text": "Node 11",
"id": "A5b3"
},
{
"text": "Node 12",
"id": "A5b4"
},
{
"text": "Node 13",
"id": "A6da"
},
{
"text": "Node 14",
"id": "A6db"
}
],
"text": "Node 1-14",
"id": "A495"
},
{
"children": [
{
"text": "Node 15",
"id": "A6dc"
},
{
"text": "Node 16",
"id": "A6dd"
},
{
"text": "Node 17",
"id": "A6de"
},
{
"text": "Node 18",
"id": "A6df"
},
{
"text": "Node 19",
"id": "A6e0"
},
{
"text": "Node 20",
"id": "A6e1"
},
{
"text": "Node 21",
"id": "A6e2"
},
{
"text": "Node 22",
"id": "A6e3"
}
],
"text": "Node 15-22",
"id": "A496"
},
{
"text": "Node 23",
"id": "A497"
},
{
"text": "Node 24",
"id": "A498"
}
],
"text": "Node 23-24",
"id": "A492"
}
],
"text": "Node 1-24",
"id": "A490"
}
如何删除整个节点,包括儿童?另外,有没有更好的方法来实现这一目标?
答案 0 :(得分:0)
您可以通过父参考
轻松完成const deepMap = (arr, fn) => {
return arr.reduce((first, second) => first.concat(Array.isArray(second) ? [deepMap(second, fn)] : fn(second)), []);
}
const res = deepMap([4,5, [3,4,[2]]], x => x + 5);
console.log(res)