Question

INSERT INTO temp_table( 
    case_id, 
    task, 
    Question,
    qa_analyst 
) 
VALUES (
    SELECT 'tt.case_id','tt.Task','abc.questions','tt.qa_analyst'
    FROM (
        SELECT DISTINCT task,questions
        FROM task_questions
    ) abc
    JOIN temp_table tt ON 'abc.task' = 'tt.Task'
)

Answer 1

有一个INSERT ... SELECT声明。它应该像这样工作：

public class MatchResults
{
    public string MatchAdmin { get; set; }
    public string Error { get; set; }
    public int allotHome { get; set; }
    public int allotAway { get; set; }
    public bool StrikeOut { get; set; }
    public int StrikeOutNbrOfRounds { get; set; }
    public int homeTeamId { get; set; }
    public int awayTeamId { get; set; }
    public int MatchId { get; set; }
    public bool Hcp { get; set; }
    public bool HcpBrutto { get; set; }
    public bool Allot { get; set; }
    public bool Finished { get; set; }
    public int Lanes { get; set; }
    public string SchemeId { get; set; }
    public List<PlayerResult> HomePlayerResults { get; set; }
    public List<PlayerResult> AwayPlayerResults { get; set; }
    public List<SquadResult> HomeSquadResults { get; set; }
    public List<SquadResult> AwaySquadResults { get; set; }
}

public class PlayerResult
{
    public string LicNbr { get; set; }
    public string FirstName { get; set; }
    public string SurName { get; set; }
    public string PlayerShortName { get; set; }
    public string NameAndLicNbr { get; set; }
    public int ShirtNo { get; set; }
    public int Hcp { get; set; }
    public List<RoundResult> RoundResults { get; set; }
}

public class RoundResult
{
    public int Round { get; set; }
    public int Result { get; set; }
    public int Table { get; set; }
    public int Squad { get; set; }
    public int RoundNbr { get; set; }
}

从多个表中选择值后如何插入

1 个答案: