我正在尝试并行化一个名为streamcluster的程序。更具体地说,名为pgain的函数根据我使用的Scalasca工具花费程序的大部分时间,所以这是我应该并行化的函数。在这里,您可以看到功能和我在并行化方面的努力。问题是,我唯一能做到的就是花更多时间执行的程序。
streamcluster中的原始pgain函数:
double pgain ( long x, Points *points, double z, long int *numcenters )
{
int i;
int number_of_centers_to_close = 0;
static double *work_mem;
static double gl_cost_of_opening_x;
static int gl_number_of_centers_to_close;
int stride = *numcenters + 2;
//make stride a multiple of CACHE_LINE
int cl = CACHE_LINE/sizeof ( double );
if ( stride % cl != 0 ) {
stride = cl * ( stride / cl + 1 );
}
int K = stride - 2 ; // K==*numcenters
//my own cost of opening x
double cost_of_opening_x = 0;
work_mem = ( double* ) malloc ( 2 * stride * sizeof ( double ) );
gl_cost_of_opening_x = 0;
gl_number_of_centers_to_close = 0;
/*
* For each center, we have a *lower* field that indicates
* how much we will save by closing the center.
*/
int count = 0;
for ( int i = 0; i < points->num; i++ ) {
if ( is_center[i] ) {
center_table[i] = count++;
}
}
work_mem[0] = 0;
//now we finish building the table. clear the working memory.
memset ( switch_membership, 0, points->num * sizeof ( bool ) );
memset ( work_mem, 0, stride*sizeof ( double ) );
memset ( work_mem+stride,0,stride*sizeof ( double ) );
//my *lower* fields
double* lower = &work_mem[0];
//global *lower* fields
double* gl_lower = &work_mem[stride];
for ( i = 0; i < points->num; i++ ) {
float x_cost = dist ( points->p[i], points->p[x], points->dim ) * points->p[i].weight;
float current_cost = points->p[i].cost;
if ( x_cost < current_cost ) {
// point i would save cost just by switching to x
// (note that i cannot be a median,
// or else dist(p[i], p[x]) would be 0)
switch_membership[i] = 1;
cost_of_opening_x += x_cost - current_cost;
} else {
// cost of assigning i to x is at least current assignment cost of i
// consider the savings that i's **current** median would realize
// if we reassigned that median and all its members to x;
// note we've already accounted for the fact that the median
// would save z by closing; now we have to subtract from the savings
// the extra cost of reassigning that median and its members
int assign = points->p[i].assign;
lower[center_table[assign]] += current_cost - x_cost;
}
}
// at this time, we can calculate the cost of opening a center
// at x; if it is negative, we'll go through with opening it
for ( int i = 0; i < points->num; i++ ) {
if ( is_center[i] ) {
double low = z + work_mem[center_table[i]];
gl_lower[center_table[i]] = low;
if ( low > 0 ) {
// i is a median, and
// if we were to open x (which we still may not) we'd close i
// note, we'll ignore the following quantity unless we do open x
++number_of_centers_to_close;
cost_of_opening_x -= low;
}
}
}
//use the rest of working memory to store the following
work_mem[K] = number_of_centers_to_close;
work_mem[K+1] = cost_of_opening_x;
gl_number_of_centers_to_close = ( int ) work_mem[K];
gl_cost_of_opening_x = z + work_mem[K+1];
// Now, check whether opening x would save cost; if so, do it, and
// otherwise do nothing
if ( gl_cost_of_opening_x < 0 ) {
// we'd save money by opening x; we'll do it
for ( int i = 0; i < points->num; i++ ) {
bool close_center = gl_lower[center_table[points->p[i].assign]] > 0 ;
if ( switch_membership[i] || close_center ) {
// Either i's median (which may be i itself) is closing,
// or i is closer to x than to its current median
points->p[i].cost = points->p[i].weight * dist ( points->p[i], points->p[x], points->dim );
points->p[i].assign = x;
}
}
for ( int i = 0; i < points->num; i++ ) {
if ( is_center[i] && gl_lower[center_table[i]] > 0 ) {
is_center[i] = false;
}
}
if ( x >= 0 && x < points->num ) {
is_center[x] = true;
}
*numcenters = *numcenters + 1 - gl_number_of_centers_to_close;
} else {
gl_cost_of_opening_x = 0; // the value we'll return
}
free ( work_mem );
return -gl_cost_of_opening_x;
}
这就是我所做的并行化:
double pgain ( long x, Points *points, double z, long int *numcenters )
{
int i;
int number_of_centers_to_close = 0;
static double *work_mem;
static double gl_cost_of_opening_x;
static int gl_number_of_centers_to_close;
int stride = *numcenters + 2;
//make stride a multiple of CACHE_LINE
int cl = CACHE_LINE/sizeof ( double );
if ( stride % cl != 0 ) {
stride = cl * ( stride / cl + 1 );
}
int K = stride - 2 ; // K==*numcenters
//my own cost of opening x
double cost_of_opening_x = 0;
work_mem = ( double* ) malloc ( 2 * stride * sizeof ( double ) );
gl_cost_of_opening_x = 0;
gl_number_of_centers_to_close = 0;
/*
* For each center, we have a *lower* field that indicates
* how much we will save by closing the center.
*/
int count = 0;
for ( int i = 0; i < points->num; i++ ) {
if ( is_center[i] ) {
center_table[i] = count++;
}
}
work_mem[0] = 0;
//now we finish building the table. clear the working memory.
memset ( switch_membership, 0, points->num * sizeof ( bool ) );
memset ( work_mem, 0, stride*sizeof ( double ) );
memset ( work_mem+stride,0,stride*sizeof ( double ) );
//my *lower* fields
double* lower = &work_mem[0];
//global *lower* fields
double* gl_lower = &work_mem[stride];
float x_cost=0.0;
float current_cost=0.0;
#pragma omp parallel for private(current_cost,x_cost)
shared(cost_of_opening_x)
for ( i = 0; i < points->num; i++ ) {
x_cost = dist ( points->p[i], points->p[x], points->dim ) * points->p[i].weight;
current_cost = points->p[i].cost;
if ( x_cost < current_cost ) {
// point i would save cost just by switching to // x
// (note that i cannot be a median,
// or else dist(p[i], p[x]) would be 0)
switch_membership[i] = 1;
cost_of_opening_x += x_cost - current_cost;
{
#pragma omp flush(cost_of_opening_x)
}
} else {
// cost of assigning i to x is at least current assignment cost of i
// consider the savings that i's **current** median would realize
// if we reassigned that median and all its members to x;
// note we've already accounted for the fact that the median
// would save z by closing; now we have to subtract from the savings
// the extra cost of reassigning that median and its members
int assign = points->p[i].assign;
lower[center_table[assign]] += current_cost - x_cost;
{
#pragma omp flush(lower)
}
}
#pragma omp barrier
{
#pragma omp flush(lower,cost_of_opening_x)
}
}
// at this time, we can calculate the cost of opening a center
// at x; if it is negative, we'll go through with opening it
for ( int i = 0; i < points->num; i++ ) {
if ( is_center[i] ) {
double low = z + work_mem[center_table[i]];
gl_lower[center_table[i]] = low;
if ( low > 0 ) {
// i is a median, and
// if we were to open x (which we still may not) we'd close i
// note, we'll ignore the following quantity unless we do open x
++number_of_centers_to_close;
cost_of_opening_x -= low;
}
}
}
//use the rest of working memory to store the following
work_mem[K] = number_of_centers_to_close;
work_mem[K+1] = cost_of_opening_x;
gl_number_of_centers_to_close = ( int ) work_mem[K];
gl_cost_of_opening_x = z + work_mem[K+1];
// Now, check whether opening x would save cost; if so, do it, and
// otherwise do nothing
if ( gl_cost_of_opening_x < 0 ) {
// we'd save money by opening x; we'll do it
#pragma omp parallel for
for ( int i = 0; i < points->num; i++ ) {
bool close_center = gl_lower[center_table[points->p[i].assign]] > 0
;
if ( switch_membership[i] || close_center ) {
// Either i's median (which may be i itself) is closing,
// or i is closer to x than to its current median
points->p[i].cost = points->p[i].weight * dist ( points->p[i],
points->p[x], points->dim );
points->p[i].assign = x;
}
}
for ( int i = 0; i < points->num; i++ ) {
if ( is_center[i] && gl_lower[center_table[i]] > 0 ) {
is_center[i] = false;
}
}
if ( x >= 0 && x < points->num ) {
is_center[x] = true;
}
*numcenters = *numcenters + 1 - gl_number_of_centers_to_close;
} else {
gl_cost_of_opening_x = 0; // the value we'll return
}
free ( work_mem );
return -gl_cost_of_opening_x;
}
你能看到任何可以加快速度的改进或改变吗?提前谢谢。
答案 0 :(得分:0)
我没有考虑你的代码逻辑(既不是串行也不是并行)。但我试图找出一些可以并行化的片段。我没有编译我建议的代码。因此,我的回答是指出一些可能性使您的代码更快。当然,必须验证,共享和私人变量必须进行分析等。基于此,我的建议是:
double pgain ( long x, Points *points, double z, long int *numcenters )
{
int i;
int number_of_centers_to_close = 0;
static double *work_mem;
static double gl_cost_of_opening_x;
static int gl_number_of_centers_to_close;
int stride = *numcenters + 2;
//make stride a multiple of CACHE_LINE
int cl = CACHE_LINE/sizeof ( double );
if ( stride % cl != 0 ) {
stride = cl * ( stride / cl + 1 );
}
int K = stride - 2 ; // K==*numcenters
//my own cost of opening x
double cost_of_opening_x = 0;
work_mem = ( double* ) malloc ( 2 * stride * sizeof ( double ) );
gl_cost_of_opening_x = 0;
gl_number_of_centers_to_close = 0;
int count = 0;
//my *lower* fields
double* lower;
//global *lower* fields
double* gl_lower;
#pragma omp parallel
{
/*
* For each center, we have a *lower* field that indicates
* how much we will save by closing the center.
*/
int i;
#pragma omp for private(i)
for ( i = 0; i < points->num; i++ ) {
if ( is_center[i] ) {
#pragma omp critical
center_table[i] = count++;
}
}
#pragma omp single
work_mem[0] = 0;
#pragma omp sections
{
//now we finish building the table. clear the working memory.
#pragma omp section
memset ( switch_membership, 0, points->num * sizeof ( bool ) );
#pragma omp section
memset ( work_mem, 0, stride*sizeof ( double ) );
#pragma omp section
memset ( work_mem+stride,0,stride*sizeof ( double ) );
}
#pragma omp single
{
lower = &work_mem[0];
gl_lower = &work_mem[stride];
}
float x_cost, current_cost;
#pragma omp for private(i, x_cost, current_cost)
for ( i = 0; i < points->num; i++ ) {
x_cost = dist ( points->p[i], points->p[x], points->dim ) * points->p[i].weight;
current_cost = points->p[i].cost;
if ( x_cost < current_cost ) {
// point i would save cost just by switching to x
// (note that i cannot be a median,
// or else dist(p[i], p[x]) would be 0)
switch_membership[i] = 1;
#pragma omp critical
cost_of_opening_x += x_cost - current_cost;
} else {
// cost of assigning i to x is at least current assignment cost of i
// consider the savings that i's **current** median would realize
// if we reassigned that median and all its members to x;
// note we've already accounted for the fact that the median
// would save z by closing; now we have to subtract from the savings
// the extra cost of reassigning that median and its members
int assign = points->p[i].assign;
#pragma omp critical
lower[center_table[assign]] += current_cost - x_cost;
}
}
// at this time, we can calculate the cost of opening a center
// at x; if it is negative, we'll go through with opening it
double low;
#pragma omp for private(i, low)
for ( int i = 0; i < points->num; i++ ) {
if ( is_center[i] ) {
low = z + work_mem[center_table[i]];
#pragma omp critical
gl_lower[center_table[i]] = low;
if ( low > 0 ) {
// i is a median, and
// if we were to open x (which we still may not) we'd close i
// note, we'll ignore the following quantity unless we do open x
#pragma omp atomic
++number_of_centers_to_close;
#pragma omp critical
cost_of_opening_x -= low;
}
}
}
#pragma omp sections
{
//use the rest of working memory to store the following
#pragma omp section
work_mem[K] = number_of_centers_to_close;
#pragma omp section
work_mem[K+1] = cost_of_opening_x;
#pragma omp section
gl_number_of_centers_to_close = ( int ) work_mem[K];
#pragma omp section
gl_cost_of_opening_x = z + work_mem[K+1];
}
// Now, check whether opening x would save cost; if so, do it, and
// otherwise do nothing
bool close_center;
if ( gl_cost_of_opening_x < 0 ) {
// we'd save money by opening x; we'll do it
#pragma omp for private(i)
for ( i = 0; i < points->num; i++ ) {
close_center = gl_lower[center_table[points->p[i].assign]] > 0 ;
if ( switch_membership[i] || close_center ) {
// Either i's median (which may be i itself) is closing,
// or i is closer to x than to its current median
points->p[i].cost = points->p[i].weight * dist ( points->p[i], points->p[x], points->dim );
points->p[i].assign = x;
}
}
#pragma omp for private(i)
for ( i = 0; i < points->num; i++ ) {
if ( is_center[i] && gl_lower[center_table[i]] > 0 ) {
is_center[i] = false;
}
}
if ( x >= 0 && x < points->num ) {
is_center[x] = true;
}
#pragma omp single
*numcenters = *numcenters + 1 - gl_number_of_centers_to_close;
} else {
#pragma omp single
gl_cost_of_opening_x = 0; // the value we'll return
}
#pragma omp single
free ( work_mem );
}
return -gl_cost_of_opening_x;
}