Question

我已经创建了一段代码，用于搜索与我的应用中地图上丢弃的相关联的电话号码：

func doCall(_ mapView : MKMapView! , didUpdateUserLocation userLocation : MKUserLocation, placemark:MKPlacemark )
{
    let request = MKLocalSearchRequest()
    let searchBar = resultSearchController!.searchBar
    request.naturalLanguageQuery = searchBar.text
    let span =  MKCoordinateSpan(latitudeDelta: 0.00000000001, longitudeDelta: 0.0000000001)
    let search = MKLocalSearch(request: request)
    search.start {MKLocalSearchResponse, error in
        for item in (MKLocalSearchResponse?.mapItems)! as [MKMapItem]
        {
            let optionalString = item.phoneNumber
            if let unwrapped = optionalString
            {

                let center = MKLocalSearchResponse!.mapItems.first!.placemark.coordinate
                request.region = MKCoordinateRegion(center: center, span: span)
                print(unwrapped)
                let cleanUrl = unwrapped.components(separatedBy: CharacterSet.decimalDigits.inverted).joined(separator: "")
                let url: URL = URL(string: "tel://" + (cleanUrl))!
                UIApplication.shared.openURL(url)
            }


    }
    }
}

然而，这段代码返回10个电话号码，并要求拨打其中的每一个。我希望代码返回与该兴趣点相关联的单个电话号码，并让我给它打电话。

Answer 1

考虑添加一个break语句。

if cleanUrl != nil {
    let cleanUrl = unwrapped.components(separatedBy: CharacterSet.decimalDigits.inverted).joined(separator: "")
    let url: URL = URL(string: "tel://" + (cleanUrl))!
            UIApplication.shared.openURL(url)
    break
}

所以，一旦电话没有。被发现，警告称不。将显示并且break语句将中断循环，并且不会显示其余电话号码的警报。

正在寻找＆amp;拨打电话号码以获取兴趣点

1 个答案: