<?php
$con = mysqli_connect("localhost","root","","register");
$sql = "SELECT * FROM photos WHERE user_id ='$id'";
$result = mysqli_query($con,$sql);
$array = mysqli_fetch_assoc($result);
$rowcount = mysqli_num_rows($result);
$source = $array['photo'];
?>
我想从colomn照片中获取数据,但如果我有多个具有相同user_id的行,$source = $array['photo']
仅从第一行返回数据。
如何从具有相同user_id的所有行获取数据?
我的数据库是:
+----+---------+----------+
| id | user_id | photo |
+----+---------+----------+
| 1 | 14 | 1010.jpg |
| 2 | 14 | 1013.jpg |
| 3 | 14 | 1210.jpg |
| 4 | 10 | 1173.jpg |
| 5 | 20 | 2038.jpg |
+----+---------+----------+
答案 0 :(得分:1)
<?php
$con = mysqli_connect("localhost","root","","register");
$sql = "SELECT * FROM photos WHERE user_id ='$id'";
$result = mysqli_query($con,$sql);
$rowcount = mysqli_num_rows($result);
while ($row = mysqli_fetch_assoc($result)) {
$source = $row['photo];
// do stuff with $source
}
?>
查看有关mysqli_fetch_assoc的文档。