Question

SELECT           USERINFO.UserID
                ,SUM(DATEDIFF(DAY, DateFrom, DateTo) + 1) AS total_leave_days
FROM            USERINFO 
INNER JOIN      CHECKINOUT ON USERINFO.USERID = CHECKINOUT.USERID 
LEFT OUTER JOIN DEPARTMENTS ON DEPARTMENTS.DEPTID = USERINFO.DEFAULTDEPTID 
left join       AuthLeave on AuthLeave.userid = userinfo.userid
                and AuthLeave.DATEFROM>='2014-01-01' 
                and AuthLeave.DATETO<='2014-06-30'

WHERE           (CHECKINOUT.CHECKTIME >= '2014-01-01') 
                AND (CHECKINOUT.CHECKTIME <= '2014-06-30') 
                AND  DEPARTMENTS.DEPTNAME = 'GEN/SUP-TBL'

GROUP BY        USERINFO.UserID

这是我的代码，我可以在下面输出

UserID  total_leave_days
35      NULL
350     NULL
30      NULL
10      735
167     NULL
21      920
1       621
224     NULL

因此我的Authleave表格数据不正确：

UserID         DATEFROM           DATETO
 1            2014-03-10     2014-03-15 
 10           2014-05-28     2014-05-29
 21           2014-05-27     2014-05-27 
 1            2014-04-10     2014-04-15

从现在起我想要输出如下：

UserID  total_leave_days
    35      NULL
    350     NULL
    30      NULL
    10      2
    167     NULL
    21      1
    1       12
    224     NULL

所以我该怎么做？

Answer 1

你能试试这个SQL

吗？

SELECT      U.[UserID],
            C.[Leave]
FROM        [USERINFO] U 
LEFT JOIN   (SELECT     [UserID],  
                        SUM(DATEDIFF(DAY,[DATEFROM],[DATETO])) [Leave]
            FROM        [CHECKINOUT]
            WHERE       [CHECKTIME] >= '2014-01-01' AND [CHECKTIME] <= '2014-06-30'
            GROUP BY    [UserID]
            ) C ON U.[USERID] = C.[USERID]
LEFT JOIN   [DEPARTMENTS] D ON D.[DEPTID] = U.[DEFAULTDEPTID] 
LEFT JOIN   [AuthLeave] A on A.[userid] = U.[userid]
WHERE       D.[DEPTNAME] = 'GEN/SUP-TBL'
enter code here

编辑：

请参阅下面的SQL，我对Table Names感到有点困惑。

SELECT      U.[UserID],
            L.[Leave]
FROM        [USERINFO] U 
JOIN        CHECKINOUT C ON U.USERID = C.USERID 
LEFT JOIN   [DEPARTMENTS] D ON D.[DEPTID] = U.[DEFAULTDEPTID] 
LEFT JOIN   (SELECT     [UserID],  
                        SUM(DATEDIFF(DAY,[DATEFROM],[DATETO])) [Leave]
            FROM        [AuthLeave]
            WHERE       [DATEFROM] >= '2014-01-01' AND [DATETO] <= '2014-06-30'
            GROUP BY    [UserID]
            ) L ON L.[UserID] =U.[UserID]
WHERE       D.[DEPTNAME] = 'GEN/SUP-TBL'
AND         C.[CHECKTIME] >= '2014-01-01' AND C.[CHECKTIME] <= '2014-06-30'

从查询中获取多行

1 个答案: