Question

我从Instagram下载了一个JSON数组结果。我需要图片网址来显示来自Instagram的帖子。我如何检索所有图片网址？

"pagination": {},
"data": [
{
  "id": "1501575131271622723_414010731",
  "user": {
    "id": "414010731",
    "full_name": "Amir_P",
    "profile_picture": "https://ig-s-b-a.akamaihd.net/hphotos-ak-xfa1/t51.2885-19/s150x150/12976101_1022789394464141_915552926_a.jpg",
    "username": "amir_p__"
  },
  "images": {
    "thumbnail": {
      "width": 150,
      "height": 150,
      "url": "https://scontent.cdninstagram.com/t51.2885-15/s150x150/e35/c100.0.880.880/18096357_1952671591631445_7945040983308107776_n.jpg"
       },

"images": {
    "thumbnail": {
      "width": 150,
      "height": 150,
      "url": "https://scontent.cdninstagram.com/t51.2885-15/s150x150/e35/c0.135.1080.1080/17268108_1309342792475888_7209542398102208512_n.jpg"
    },

Answer 1

我发现这种方式对我有用。

public function picture(Request $request)
{
    if ($request->session()->has("access_token")) {
        $access_token = $request->session()->get("access_token");
        $client = new Client();
        $res = $client->request('GET', 'https://api.instagram.com/v1/users/self/media/recent/?access_token=' . $access_token);
        if ($res->getBody()) {
            $body = $res->getBody();
            $obj = \GuzzleHttp\json_decode($body);
            $data = $obj->data;
            foreach ($data as $img) {
                $img = $img->images->thumbnail->url;
                //echo "\n";
            }
                       }

    } else {
        echo "there is no access token in session";
    }
}

使用Laravel 5.4显示JSON数组结果

1 个答案: