Question

我有来自移动端的json数据，我需要将其插入两个表orders和order_details

orders表包含单个条目，order_details表包含json object

数组

{
    "id": 1,
    "user_id": "1",
    "delivery_boy_id": "3",
    "address_type": "home",
    "address": "Address of the customer",
    "landmark": "Near Address",
    "city": "Mangalore",
    "state": "Karnataka",
    "pincode": "575002",
    "delivery_time_slot": "9am to 11am",
    "delivery_date": "23-7-2017",
    "promo_code_applied": "no",
    "payment_type": "cod",
    "transaction_details": null,
    "total": "580",
    "signature": null,
    "status": "delivered",
    "comment": null,
    "created_at": "2017-06-22 01:05:16",
    "updated_at": "2017-06-22 01:05:16",
    "order_details": [
        {
            "id": 1,
            "product_id": "1",
            "quantity": 2,
            "created_at": "2017-06-22 01:05:16",
            "updated_at": "2017-06-22 01:05:16"
        },
        {
            "id": 2,
            "product_id": "2",
            "quantity": 3,
            "created_at": "2017-06-22 01:05:16",
            "updated_at": "2017-06-22 01:05:16"
        }
    ]
}

我可以将数据保存到orders表，我想修改（追加保存的order_id）并将order_details数据保存到order_details表

public function placeOrder(Request $request)
{   
    $order = new Order;

    $order->outlet_id = $request->outlet_id;
    $order->user_id = $request->user_id;
    $order->delivery_boy_id = $request->delivery_boy_id;
    $order->address_type = $request->address_type;
    $order->address = $request->address;
    $order->landmark = $request->landmark;
    $order->city = $request->city;
    $order->state = $request->state;
    $order->pincode = $request->pincode;
    $order->delivery_time_slot = $request->delivery_time_slot;
    $order->delivery_date = $request->delivery_date;
    $order->promo_code_applied = $request->promo_code_applied;
    $order->payment_type = $request->payment_type;
    $order->transaction_details = $request->transaction_details;
    $order->total = $request->total;
    $order->signature = $request->signature;
    $order->status = $request->status;
    $order->comment = $request->comment;
    $order->save();

    //loop through the order_details array from above JSON
    //add the above saved order_id to order_details 
    //save the orers_details array in order_details table

   foreach ($request->order_details as $key => $order_detail) {

        $details = new OrderDetail;

        $details->order_id = $order->id;
        $details->product_id = $order_detail->product_id; //line 43
        $details->quantity = $order_detail->quantity;
        $details->save();

    }

    return Response::json([
        'data' => $order->id
    ]);
}

我收到以下错误

(1/1) ErrorException
Trying to get property of non-object
in OrderController.php (line 43)

谢谢

Answer 1

使用

 $details->product_id = $order_detail['product_id']
 $details->quantity =$order_detail['quantity'];

当您尝试使用 - ＆gt;访问正常数组值时会发生这种情况。操作

Laravel - 将JSON数组数据插入数据库

1 个答案: