我想在我的c ++ / qt / qml应用程序中添加一个启动画面。我添加了以下代码:
int main(int argc, char *argv[])
{
QGuiApplication app(argc, argv);
QQmlApplicationEngine engine;
QQuickView *view = new QQuickView;
view->setSource(QUrl(QLatin1String("qrc:/Splash.qml")));
view->show();
engine.load(QUrl(QLatin1String("qrc:/main.qml")));
view->close();
app.exec();
return 0;
}
Splash.qml文件:
import QtQuick 2.0
import QtQuick.Controls 2.1
Item {
visible: true
width: 640
height: 480
BusyIndicator {
anchors.centerIn: parent
width: 100
height: 100
running: true
Component.onCompleted: {
console.log("splash screen... " + x + " " + y + " " + width + "x" + height)
visible=true
}
}
}
当应用程序启动时,会打印消息:“qml:splash screen ... 270 190 100x100”,但QQuickWindow只是白色。 main.qml的主窗口可以正常工作。我试图在Splash.qml中加载图像,但同样的问题。并且,我无法使用QQuickView :: setWindowFlags使其成为无框架窗口。我正在研究win7 64位操作系统。
答案 0 :(得分:0)
你可以在QML中轻松完成:
import QtQuick 2.7
import QtQuick.Controls 2.0
import QtQuick.Window 2.0
Window {
id: mainWindow
width: 600
height: 400
visible: false
x: Screen.width / 2 - width / 2;
y: Screen.height / 2 - height / 2;
Window {
id: splashWindow
width: 300
height: 200
visible: true
x: Screen.width / 2 - width / 2;
y: Screen.height / 2 - height / 2;
flags: Qt.SplashScreen;
Rectangle {
anchors.fill: parent
color: "green";
}
ProgressBar {
id: progressBar
anchors.centerIn: parent
anchors.margins: 20
value: 0.01
}
Timer {
id: timer
interval: 50
repeat: true
running: true
onTriggered: {
progressBar.value += 0.01
if(progressBar.value >= 1.0) {
timer.stop();
mainWindow.visible = true;
splashWindow.destroy();
}
}
}
}
}