Python，如何根据列表元素的值扩展列表？

Question

我有一份地址列表

addr1=['0x00800d00', 'numb=4', '0x00800d10', '0x00800d20', 'numb=4', '0x00800d30', '0x00800d40', '0x00800e00', '0x00800e04', '0x00800e10', '0x00800e14', '0x00800e18', '0x00800e1c', '0x00800e20', '0x00800e24', '0x00800e28', '0x00800e2c', 'numb=32', '0x00800e30']

我希望根据'numb=<x>'中的值扩展列表。 即如果addr1[1]是'numb=4'，那么从addr[2]的值开始，我想从addr[2]开始填充列表中的四个地址作为 - ＆gt; '0x00800d10', '0x00800d14', '0x00800d18', '0x00800d1c' 并使用'numb='

删除元素

所以addr2应该是这样的：

addr2=['0x00800d00', '0x00800d10', '0x00800d14', '0x00800d18', '0x00800d1c', '0x00800d20', '0x00800d30', '0x00800d34','0x00800d38', '0x00800d3c', '0x00800d40',...... and so on]

Answer 1

一种可能性：

addr2 = []
numb = 1
for addr in addr1:
    if addr.startswith('numb='):
        numb = int(addr[5:])
        continue
    addr_num = int(addr, 0)
    for i in range(numb):
        addr2.append("{0:#0{1}x}".format(addr_num, 10))
        addr_num += 4
    numb = 1