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Question

说我有这样的清单：

myList = ['this\n', 'is\n', 'sparta\n']

如何在不创建新列表的情况下实现以下结果，执行某些逻辑并将其复制到...

newList = ['this', '\n', 'is', '\n', 'sparta', '\n']

Answer 1

在换行符上只拆分一次时，可以使用str.partition()生成元素列表，然后跳过所有空结果：

newList = [elem for word in myList for elem in word.partition('\n') if elem]

演示：

>>> myList = ['this\n', 'is\n', 'sparta\n']
>>> [elem for word in myList for elem in word.partition('\n') if elem]
['this', '\n', 'is', '\n', 'sparta', '\n']
>>> myList = ['this\n', 'is', 'sparta\n']
>>> [elem for word in myList for elem in word.partition('\n') if elem]
['this', '\n', 'is', 'sparta', '\n']