Question

我想在Thread中执行django的call_method。这是示例代码：

import sys
sys.path.append("/my/django/project/path/")
import threading
import time 


# Import my django project configuration settings
from django.core.management import setup_environ
from mydjangoprojectname import settings
setup_environ(settings)

from django.core.management import call_command

class ServerStarter(threading.Thread):
    def __init__(self):
        super(ServerStarter, self).__init__()
        print "ServerStarter instance created"

    def run(self):
        print "Starting Django Server..."
        call_command("runserver", noreload=True)


if __name__ == '__main__':
    starter = ServerStarter()
    starter.start()

------------------------------
OutPut:
ServerStarter instance created
Starting Django Server...
ServerStarter instance created
Starting Django Server...
Validating models...
0 errors found
Django version 1.2.3, using settings 'mydjangoprojectname.settings'
Development server is running at http://127.0.0.1:8000/
Quit the server with CONTROL-C.

Django服务器正常启动，但ServerStarter创建两次两个ServerStarter的实例都运行如果我在run方法中注释call_command（“runserver”，noreload = True），那么只有创建了一个线程（这就是我想要的）提前谢谢！

Answer 1

我找到了解决方案（Chris Morgan是对的）。这段代码按我的意思运行：

import sys
sys.path.append("/my/django/project/path/")
import threading

# Import my django project configuration settings
from django.core.management import setup_environ, ManagementUtility

from mydjangoprojectname import settings
setup_environ(settings)


class ServerStarter(threading.Thread):
    def __init__(self):
        super(ServerStarter, self).__init__()
        print "ServerStarter instance created"

    def run(self):
        print "Starting Django Server..."
        utility = ManagementUtility()
        command = utility.fetch_command('runserver')
        command.execute(use_reloader=False)


if __name__ == '__main__':
    starter = ServerStarter()
    starter.start()

Answer 2

我认为这可能是由Django内部服务器重新加载所有模块造成的。尝试--noreload call_command的等效内容（可能是call_command("runserver", noreload=True)，但我不确定）。

（同样QThread由QApplication.exec_()启动;除非您有特殊要求提前启动它，否则我认为您不应该自己运行starter.start()。）

线程中django的call_command问题

2 个答案: