Question

如何在call_command()中使用文件名通配符？我正在尝试创建一个与python manage.py loaddata */fixtures/*.json

相同的管理命令

下面的代码抛出CommandError: No fixture named '*' found.

from django.core.management import call_command
from django.core.management.base import BaseCommand


class Command(BaseCommand):
    help = 'Load all fixtures in app directories'

    def handle(self, *args, **kwargs):
        call_command('loaddata', '*/fixtures/*.json')
        self.stdout.write('Fixtures loaded\n')

Answer 1

python manage.py loaddata */fixtures/*.json命令中的glob输入起作用是因为bash被bash扩展了；如果您尝试转义glob，例如python manage.py loaddata '*/fixtures/*.json'，该命令应失败并显示相同的错误消息。

相反，扩展Python端的glob，例如：

import pathlib

class Command(BaseCommand):
    help = 'Load all fixtures in app directories'

    def handle(self, *args, **kwargs):
        cmd_args = list(pathlib.Path().glob('*/fixtures/*.json'))
        call_command('loaddata', *cmd_args)

带有文件名通配符的Django call_command（）

1 个答案: