Question

我想检查一个句子是否有一个数组项，是一个bigram / trigram ，来自words数组，并且包含数组项的bigram / trigram在一起句子。

words = ["foo", "bar", "spooky", "rick james"]
sentence = say hello to rick james but not rick and james

由于rick james是一个数组项，并且在一起，所以预期的输出应该是

false #say
false #hello
false #to
true #rick <---
true #james <---
false #but
false #not
false #rick <---
false #and
false #james <---

我试过这个

# BASIC EXAMPLE
words = ["foo", "bar", "spooky", "rick james"]

sentence = "something spooky rick this way comes, rick james"

sentence.split.each {|s| puts words.include?(s) }

# OUTPUT                      #EXPECTED OUTPUT
false #something              false
true #spooky <---             true  #spooky
false #rick                   false  #rick
false #this                   false
false #way                    false
false #comes                  false
false #rick                   true  #rick <---
false #james                  true  #james <---

要修改哪些内容以包含预期输出

Answer 1

如果您的域名为bigrams / trigrams，则应将该句子拆分为bigrams / trigrams。

Enumareable#each_cons(n)可能会对你有所帮助（我会把n = 2用于双胞胎）

sentence = "say hello to rick james but not rick and james"
split.each_cons(2) {|e| puts "#{e.join(" ")}" }

# say hello
# hello to
# to rick
# rick james
# james but
# but not
# not rick
# rick and
# and james

如果将bi / trigrams作为一个整体包含在内，则意味着它的词汇也包括在内。

words = ["foo", "bar", "spooky", "rick james"]   
sentence.split.each_cons(2) do |e| 
  puts "#{e} => #{words.include?(e)||words.include?(e.join(" "))}"
end

# ["say", "hello"] => false
# ["hello", "to"] => false
# ["to", "rick"] => false
# ["rick", "james"] => true
# ["james", "but"] => false
# ["but", "not"] => false
# ["not", "rick"] => false
# ["rick", "and"] => false
# ["and", "james"] => false

然后您可以获取这些数组元素并为每个元素返回true / flase

Answer 2

也许你可以搜索（.include？）或（.include_in？）数组中每个单词的句子。这样你就可以搜索.include？（＆＃34; rick james＆＃34;）

Ruby检查句子是否有来自数组的单词bigram / trigram

2 个答案: