Question

我有一系列停用词：

myArray = ["","a","ago","also","am","an","and","ani","ar","aren't","arent","as","ask","at","did","didn't","didnt","do","doe","would","be","been","best","better"]

我想从句子中删除匹配的项目：

str = 'A something and hello'

所以它变成了：

'something hello'

1。我怎么能用ruby做到这一点？

2. 我怎样才能为一个字符数组（删除所有匹配的字符）执行此操作？

这是字符数组：

["(",")","@","#","^"]

Answer 1

sentence = 'A something and hello'
array  = ["","a","ago","also","am","an","and","ani","ar","aren't","arent",
          "as","ask","at","did","didn't","didnt","do","doe","would",
          "be","been","best","better"]


sentence.split.delete_if{|x| array.include?(x)}.join(' ')

 => "A something hello"

你可能想要在比较之前将所有单词放在一边，以摆脱句子开头的“A”：

sentence.split.delete_if{|x| array.include?(x.downcase)}.join(' ')

 => "something hello"

如果你有一个字符串数组，那就更容易了：

(sentence.split - array).join(' ')
=> "A something hello"    #  but note that this doesn't catch the "A"

还删除特殊字符：

special = ["(",")","@","#","^"]

sentence.split.delete_if{|x| array.include?(x.downcase) || special.include?(x) }.join(' ')

删除单词或短语的另一种方法是：

array.each do |phrase|
  sentence.gsub!(/#{phrase}/,'')
end

Answer 2

Tilo的答案的单行变体是干净且不区分大小写的（尽管它返回所有小写输出，这可能不是所有用途的理想选择）：

(sentence.downcase.split - array).join(' ')

Answer 3

我的解决方案：

stop_words = ["","a","ago","also","am","an","and","ani","ar","aren't","arent","as","ask","at","did","didn't","didnt","do","doe","would","be","been","best","better"]
output = %w(A something and hello) - stop_words

Answer 4

 array.map {|s| s.gsub(keyword, '')}

如何从句子中删除单词数组？

4 个答案: