我使用PHP将JSON对象返回给Javascript,我想循环遍历该对象,然后在代码中打印每个值。
这是功能:
// Define things a user *has* to be able to do (has to implement)
interface iUser {
public function set();
public function get();
public function setTable();
}
// Define our default abstraction
abstract class DefaultUser implements iUser {
private $_username = false;
private $_userid = false;
protected $_table = false;
public function get() {
/* the default implementation */
echo "defaultUser get";
}
public function set() {
echo "defaultUser set";
}
}
class UserAdmin extends DefaultUser {
public function setTable($table) {
$this->_table = $table;
}
public function set() {
echo "UserAdmin's set() and also my parent's set()";
parent::set();
}
public function get() {
echo "UserAdmin's get() and also my parent's get()";
parent::get();
}
}
class UserCMS extends DefaultUser {
public function setTable($table) {
$this->_table = $table;
}
public function set() {
echo "UserCMS's set() and also my parent's set()";
parent::set();
}
public function get() {
echo "UserCMS's get() and also my parent's get()";
parent::get();
}
}
如您所见,标签:[]为空,我需要从JSON数组中提取值并将它们添加到'[]'。
我通过AJAX返回JSON,所以我想我不能使用PHP来遍历对象。
答案 0 :(得分:1)
下面的代码使用JSON中的labels
值填充label
数组
var json = [{
label: 'FiveRP',
data: [],
backgroundColor: "rgba(75,192,192,0.4)",
fill: false,
lineTension: 0.1,
borderColor: "rgba(75,192,192,1)",
borderCapStyle: 'butt'
}, {
label: 'GTALife',
data: [],
backgroundColor: "rgba(148,0,211,0.4)",
fill: false,
lineTension: 0.1,
borderColor: "rgba(148,0,211,1)",
borderCapStyle: 'butt'
}, {
label: 'GermanV',
data: [],
backgroundColor: "rgba(255,165,0,0.4)",
fill: false,
lineTension: 0.1,
borderColor: "rgba(255,165,0,1)",
borderCapStyle: 'butt'
}];
var arr = [];
for (e of json) {
arr.push(e.label)
}
var data = {
labels: arr,
datasets: json
}
console.log(data.labels);