Question

我有一个Json数组，在每个对象上我想相应地编辑特定键的值

例如，我如何循环遍历此数组并编辑＆＃34; unix_time＆＃34;每个对象的关键。

[{"_id":"","__v":0,"read":false,"timestamp":"","unix_time":"1477924542020"},
{"_id":"","__v":0,"read":false,"timestamp":"","unix_time":"1477924542020"},
{"_id":"","__v":0,"read":false,"timestamp":"","unix_time":"1477924532440"}, 
...
...
... ]

Answer 1

以下是测试类。如果有帮助，请告诉我

package com.test;

import org.json.JSONArray;
import org.json.JSONObject;

public class JSONTest {
public static void main(String[] args){
JSONArray jsonArray = new JSONArray();
JSONObject j1 = new JSONObject();
j1.put("id", "1");
j1.put("read", "false");
j1.put("time", "143250176");
jsonArray.put(j1);

JSONObject j2 = new JSONObject();
j2.put("id", "2");
j2.put("read", "false");
j2.put("time", "143250177");
jsonArray.put(j2);

JSONObject j3 = new JSONObject();
j3.put("id", "3");
j3.put("read", "false");
j3.put("time", "143250178");
jsonArray.put(j3);

JSONArray newArray = new JSONArray();
for(int count=0; count<jsonArray.length(); count++)
{
    JSONObject localInstance = jsonArray.getJSONObject(count);
    if(localInstance.optString("time") != "")
    {
        String time = localInstance.getString("time");
        String newTime = "new "+time;
        localInstance.put("time", newTime);
        newArray.put(localInstance);
    }
}
System.out.println(newArray);
}
}

Answer 2

尝试：

public class TransfomerService
{
    MessageXTransformer messageXTransformer = new MessageXTransformer();
    MessageYTransformer messageYTransformer = new MessageYTransformer();

    public CanonicalMessage transform(VendorMessage message)
    {
        if (message instanceOf MessageA)
        {
            return messageXTransformer.transform((MessageA) message);
        }
        else if (message instanceOf MessageB)
        {
            return messageYTransformer.transform((MessageB) message);
        }
    }
}

Java循环通过JSON数组并编辑值

2 个答案: