Question

我有字符串

str = 'ab created > 2017-04-22 AND creator ="abc" ORDER BY reporter'

我需要的是，我想删除以ORDER开头的子字符串..

结果：

str = 'ab created > 2017-04-22 AND creator ="abc"'
subString = 'ORDER BY reporter'

Answer 1

使用str.indexOf()和str.substring()执行此操作，类似于：

var str = "ab created > 2017-04-22 AND creator ='abc' ORDER BY reporter"

var order_str = str.substring(str.indexOf('ORDER') );
var new_str = str.substring(0, str.indexOf('ORDER'));

console.log(order_str,'\n', new_str);

Answer 2

你需要逃避你的报价，但你可以这样做：

const newStr = str.replace(/ORDER BY.+/, '')

Answer 3

试试这个：

str = str.substring(0, str.indexOf("ORDER BY reporter"))

返回'ab created > 2017-04-22 AND creator ="abc" '。如果您还需要删除尾随空格，请改为：

str = str.substring(0, str.indexOf("ORDER BY reporter")-1)

Answer 4

var str = 'ab created > 2017-04-22 AND creator ="abc" ORDER BY reporter'


function SliceMe(origStr,slicer){

var result =origStr.slice(0,origStr.indexOf(slicer));

var result1 =origStr.slice(origStr.indexOf(slicer));

console.log(origStr)
console.log("result: " +result)
console.log("result1 : " + result1)

}

SliceMe(str,"ORDER");

Answer 5

<script>
    var str = 'ab created > 2017-04-22 AND creator ="abc" ORDER BY reporter';
    console.log(str);
    var subString = str.substring(str.indexOf("ORDER"));
    console.log(subString);
    var str = str.substring(0,str.indexOf("ORDER"));
    console.log(str);
</script>

获取以特定文本

5 个答案: