在某个子字符串之后获取字符串

Question

如何在某个子字符串之后获取字符串：

strings = ["Mayo", "Nice May", "nice May comes", "nice Mayo", "nice Mayo comes"]
substring = "May"

我只想获取其中带有“ May”一词的字符串，并且不仅包含序列“ May” 。

我尝试了以下代码：

for x in strings:
    if "May" in x:
        print(x)

for x in strings:
    if x.find("May"):
        print(x)

我想要：

Nice May                                                                                                                       

nice May comes

我得到：

Mayo                                                                                                                               
Nice May                                                                                                                           
nice May comes                                                                                                                     
nice Mayo                                                                                                                          
nice Mayo comes                                                                                                                    
abcMayabc

Answer 1

使用split()，检查substring是否为in的{​​{1}}的{​​{1}}，并用空格隔开：

elem

输出：

strings

使用strings = ["Mayo", "Nice May", "nice May comes", "nice Mayo", "nice Mayo comes"] substring = "May" for x in strings: if substring in x.split(" "): print(x) ：

Nice May
nice May comes

输出：

list comprehension

Answer 2

使用正则表达式边界。

例如：

import re

strings = ["Mayo", "Nice May", "nice May comes", "nice Mayo", "nice Mayo comes"]
substring = "May"

for i in strings:
    if re.search(r"\b{}\b".format(substring), i):
        print(i)

输出：

Nice May
nice May comes